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2 years ago

In the triangle of ABC, D is a point on AB , AC = 7, AD = 6, and BC = 18. The length of DB could be

Mathematics

1 answer:

Ray Of Light [21]2 years ago

8 0

Answer:

19 > DB > 5

Step-by-step explanation:

In a triangle Δ ABC, AC = 7, and BC = 18.

Therefore, the length of the third side of the triangle Δ ABC i.e. length of AB can have a maximum value of < (7 + 18) i.e. 25 and the minimum value of the length AB will be > (18 - 7) i.e. 11

Hence, the length of AB will be given by 25 > AB > 11.

Now, AB = AD + DB = 6 + DB {Since length of AD is given to be 6}

Therefore, 25 > 6 + DB > 11

⇒ 19 > DB > 5 (Answer)

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1 year ago

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3 years ago

g For the curve parameterized by x(t) = 3 sin t, y(t) = 5 cost, for −π/4 ≤ t ≤ π/2: (a) Sketch the curve and the direction trace

tamaranim1 [39]

Answer:

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Step-by-step explanation:

a) Points moves clockwise as t increases. See the curve in the file attached below. The parametric equations describe an ellipse.

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$s = \int\limits^{0.5\pi}_{-0.25\pi} {[\left( 3\cdot \cos t\right)^{2}+\left(-5\cdot \sin t \right)^{2}]} \, dx$

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3 years ago

The measure on angle 0 is 7pie/4. Measure of its reference angle is __ °, and the tan 0 is ___

soldier1979 [14.2K]

Answer:

Reference angle is $\frac{\pi }{4}$ and tan $\frac{7\pi }{4}$ = -1

Step-by-step explanation:

$\frac{7\pi }{4}$ lies in the 4th quadrant

and reference angle for angle in 4th quadrant is 2π - x , where x is the angle given.

and reference angle for $\frac{7\pi }{4}$ is

2π- $\frac{7\pi }{4}$ = $\frac{\pi }{4}$

and tan $\frac{7\pi }{4}$ = -tan $\frac{\pi }{4}$ = -1

Since tan is negative in 4th quadrant ,therefore value will be negative for the given angle.

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3 years ago