Volume of a cone is equal to pi*r^2*(h/3)
3.14*5^2*2/3 = 52.36 cubic cm.
Density = mass/volume
6 grams/ 52.36 cm^3= 0.1146
Round to 2 decimal places to get D.0.11 g/cm^3
Answer:
The bounded area is 5 + 5/6 square units. (or 35/6 square units)
Step-by-step explanation:
Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)
Such that f(x) > g(x) in the given interval.
This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).
We want to find the area bounded by:
f(x) = y = x^2 + 1
g(x) = y = x
x = -1
x = 2
To find this area, we need to f(x) - g(x) between x = -1 and x = 2
This is:


We know that:



Then our integral is:

The right side is equal to:

The bounded area is 5 + 5/6 square units.
Down and maximum I think I know down is right for sure but I’m not sure about the other one