Solve for y.<br> -3 =7 (У

Help Me With These #Geometry

cluponka [151]

#4 is b. you use the law of sines to find the missing angles and side lengths.

8 0

3 years ago

Find the value of x for the right triangle. Round your answer to the nearest hundredth

Anna007 [38]

Answer:38.56

Step-by-step explanation:

tan35=opposite ➗ adjacent

0.7002=27 ➗ x

Cross multiplying we get

0.7002(x)=27

Divide both sides by 0.7002

0.7002x ➗ 0.7002=27 ➗ 0.7002

x=38.56041131

x=38.56 nearest hundredth

7 0

3 years ago

Cual ecuacion representa un ejemplo de la

Katarina [22]

Answer:

B) 6(x+2y) + 4 = 6x + 12 y + 4

6 0

3 years ago

M<5=? what’s it equal

WINSTONCH [101]

Answer:

<8

Step-by-step explanation:

They are the same angle degree.

5 0

2 years ago

A random sample of 144 recent donations at a certain blood bank reveals that 81 were type A blood. Does this suggest that the ac

Reptile [31]

Answer:

Null hypothesis: $p=0.4$

Alternative hypothesis: $p \neq 0.4$

$z=\frac{0.5625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{144}}}=3.98$

$p_v =2*P(z>3.98)=0.0000689$

Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%

Step-by-step explanation:

Information given

n=144 represent the random sample taken

X=81 represent the number of people with type A blood

$\hat p=\frac{81}{144}=0.5625$ estimated proportion of people with type A blood

$p_o=0.4$ is the value that we want to verify

$\alpha=0.01$ represent the significance level

z would represent the statistic

$p_v{/tex} represent the p value Hypothesis to testWe want to test if the percentage of the population having type A blood is different from 40%.: Null hypothesis:[tex]p=0.4$

Alternative hypothesis: $p \neq 0.4$

the statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.5625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{144}}}=3.98$

Now we can calculate the p value with this probability taking in count the alternative hypothesis:

$p_v =2*P(z>3.98)=0.0000689$

Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%

3 0

3 years ago

Solve for y. -3 =7 (У - 9/7)