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masha68 [24]
2 years ago
12

After substituting, what is the first operation performed when evaluating 5 + (9 x minus 3) divide 2 for x = 5? addition multipl

ication subtraction division
Mathematics
2 answers:
adelina 88 [10]2 years ago
7 0

Answer:

Multiplication

Step-by-step explanation: I took the test

ludmilkaskok [199]2 years ago
4 0

Answer:

<h2>Multiplication.</h2>

Step-by-step explanation:

The given expression is

5+(9x-3) \div 2

For x=5, we have

5+(9(5)-3) \div 2

Notice that the first operation we need to do is multiplication, because that's the right order of operations when we solve these kind of expressions.

5+(45-3) \div 2

Then, we subtract

5+42 \div 2

Now, we divide

5+21

Finally, we sum

26

Therefore, the right answer is multiplication.

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11/15 = 0.73

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3 years ago
Suppose that 10% of all homeowners in an earthquake-prone area of California are insured against earthquake damage. Four homeown
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Remainder of question:

Find the probability distribution of x

Answer:

The random variable x is defined as: X = {0, 1, 2, 3, 4}

The probability distribution of X:

P(X = 0) = 0.656

P(X = 1) = 0.2916

P(X= 2) = 0.0486

P(X=3) = 0.0036

P(X = 4) = 0.0001

Step-by-step explanation:

Sample size, n = 4

Random variable, X = {0, 1, 2, 3, 4}

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Proportion of homeowners who are not insured against earthquake, q = 1 - 0.1

q = 0.9

Probability distribution of x,

P(X = r) = ^nC_r *p^r q^{n-r} \\\\P(X= 0) =(^4C_0 *p^1 q^4 )\\P(X=0) = (^4C_0 *0.1^0 0.9^4 ) = 0.656\\P(X= 1)= (^4C_1 *p^1 q^3 )\\P(X=1) = (^4C_1 *0.1^1 0.9^3 ) = 0.2916\\P(X= 2)=( ^4C_2 *p^2 q^2) \\P(X=2) = (^4C_2 *0.1^2 0.9^2 ) = 0.0486\\P(X= 3) = (^4C_3 *p^3 q^3) \\ P(X=3) = (^4C_3 *0.1^3 0.9^1 ) = 0.0036\\P(X= 4) =  (^4C_4 *p^4 q^0 )\\ P(X=4) =(^4C_4 *0.1^4 0.9^0 ) = 0.0001

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3 years ago
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Step-by-step explanation:

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Answer:

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