All categories

3 years ago

Find the exact circumference of a circle with the given radius.

Mathematics

1 answer:

gtnhenbr [62]3 years ago

5 0

It should be 31.41 bc the equation is 2•pi•radius

You might be interested in

X equals 15 and z equals 7 <br><br><img src="https://tex.z-dn.net/?f=%20%7Bz%7D%5E%7B2%7D%20%20%2B%203%20%5C%3A%20%28x%20-%20z%2

Nikitich [7]

I believe the answer is 241.

8 0

3 years ago

Read 2 more answers

A tea company is making a special blend of two teas for a customer. The ratio of green tea to peppermint tea in the blend is 2 t

dedylja [7]

There is 40 ounces of Green tea and 50 ounces of peppermint tea. Good luck!

3 0

4 years ago

Read 2 more answers

Can you please help me with this I will mark the BRAINLIEST who ever can help thanks

son4ous [18]

$QUESTION:$

$WORK$ $OUT$ $THE$ $VALUE$ $OF$ $2^{6}$

Or 2 times 2 times 2 times 2 times 2 times 2 times 2

$ANSWER:$

So, 2^6 is:

Now, 7^4 is:

2,401

Hope it helps!

$Grace Rosalia$

5 0

3 years ago

Read 2 more answers

Give an example of where you would use either the Commutative or Associative Property of Addition in a real world situation.

umka2103 [35]

So the best I could come up with is paper-rock-scissors; the operation takes two inputs and puts out the winner (assuming they are different).

So (paper rock) scissors= paper scissors = scissors,

But paper (rock scissors)= paper rock = paper.

This is a good example because it shows that associativity matters even outside of math.

3 0

3 years ago

Solve x4 – 17x2 + 16 = 0.<br> Let u =<br> Select all of the zeroes of the function. i i

Soloha48 [4]

$Solve \ x^4 - 17x^2 + 16 = 0$

To solve this equation , we need to write it in quadratic form

$ax^2+bx+c=0$

To get the equation in quadratic form we replace x^2 with u

$x^2 = u$

$x^4 - 17x^2 + 16 = 0$ can be written as

$(x^2)^2 - 17x^2 + 16 = 0$ , Replace u for x^2

So equation becomes

$u^2 - 17u + 16 = 0$

Now we factor the left hand side

-16 and -1 are the two factors whose product is +16 and sum is -17

(u-16) (u-1) = 0

u -16 = 0 so u=16

u-1 =0 so u=1

WE assume u = x^2, Now we replace u with x^2

$u = 16 so \ it \ becomes \ x^2 =16$

Now take square root on both sides , x= +4 and x=-4

$u = 1 so \ it \ becomes \ x^2 =1$

Now take square root on both sides , x= +1 and x=-1

So zeros of the function are -4, -1, 1, 4

8 0

3 years ago

Read 2 more answers