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polet [3.4K]
2 years ago
5

Professor shepherd weighed two pieces of metal for an experiment. the piece of iron weighed 7/12 of a pound and the piece of alu

minum weighed 1/2 of a pound. how much more did the piece of iron weigh than the piece of aluminum?
Mathematics
1 answer:
Ira Lisetskai [31]2 years ago
6 0

Answer:

The iron weighed 1/12 pound more than the aluminum.

Step-by-step explanation:

The weight of the aluminum is given as 1/2 pound. But that can also be written as 6/12 pound.

This is a subtraction problem (subtracting fractions...so also a common denominator problem)

In order to subtract fractions you have to get a common denominator.

7/12 - 1/2

= 7/12 - 6/12

= 1/12

The iron is 1/12 pound heavier than the aluminum.

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Answer:

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What is the 32nd term of the arithmetic sequence where<br> a1 = 14 and a13 = -58?
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n_{th}\ term=a+(n-1)d
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So, the 32nd term is:
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5 0
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Select the locations on the number line to plot the points 9/2 and −7/2 .
myrzilka [38]
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8 0
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Solve for x and y 9/x-4/y=8
borishaifa [10]
You can solve <span>9/x-4/y=8 for x or for y but NOT at the same time.

Solving for x:  </span><span>9/x-4/y=8       Mult all 3 terms by xy to eliminate the fractions.

9(xy)/x - 4xy/y = 8xy         =>       9y - 4x = 8xy, or 9y = 4x + 8xy = 4x(1+2y)

                                                                        then 9y = x [ 4(1+2y) ]
                                                                                     9y
                                                            therefore x = ------------
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Solve for y using a similar approach.

</span>
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