(1/A) dA/dt= C where A is the population of ants and C is a constant
ln(A) = C*t + C1 where C1 is another constant that comes out of integration and t is time in days.
Plugging in: at t=0, A= 100 so C1 = ln(100) = 4.605
at t=3, A=230 so ln(230) = 3*C +4.605 so C = 0.278
Final equation:
ln(A) = 0.278t + 4.605
or:
A = exp(0.278t + 4.605)
After 14 days, A = exp(0.278*14 + 4.605) = 4875.2
Answer:
There are an infinite number of values satisfying the requirements; every couple of numbers satisfying the following conditions are valid:
base = 60-w meters
width = w meters
0 < w <= 22
Step-by-step explanation:
Since the playground has a rectangular shape, let us us call b the base of the rectangle and w its width. In order for the rectangle to satisfy the condition of P = 120, we need for the following equation to satisfy:
2b + 2w = 120
Solving for b, we get that b = (120 - 2w)/2 = 60 - w .
Given a particular value (w) for the width, the base has to be: (60-w).
Therefore, the possible lengths of the playground are (60-w, w), where 60-w corresponds to the base of the rectangle and w to its width. And w can take any real value from 0 to 22.
Answer:
it hink it would be 30.6. but i'm not really sure is this a muliple question
Answer:
one
Step-by-step explanation:
When a system of equations is graphed, the solution is the coordinate that is plotted at the intersection of the two lines.
If the two lines cross once, there is only one solution.
If the two lines are on top of each other then there are infinitely many solutions.
If the two lines are parallel ( and never touch ) then there are no solutions
By looking at the graph we notice the two lines intersect once. So we can conclude that there is only one solution.