(a) converges; consider the function <em>f(x)</em> = <em>a</em> ˣ, which converges to 0 as <em>x</em> gets large for |<em>a</em> | < 1. Then the limit is 2.
(b) converges; we have
4ⁿ / (1 + 9ⁿ) = (4ⁿ/9ⁿ) / (1/9ⁿ + 9ⁿ/9ⁿ) = (4/9)ⁿ × 1/(1/9ⁿ + 1)
As <em>n</em> gets large, the exponential terms vanish; both (4/9)ⁿ → 0 and 1/9ⁿ → 0, so the limit is 1.
(c) converges; we know ln(<em>n</em> ) → ∞ and arctan(<em>n</em> ) → <em>π</em>/2 as <em>n</em> → ∞. So the limit is <em>π</em>/2.
answer:
78
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Answer:
look at the attached image
Step-by-step explanation:
Let's call one number x and one number y.
x/2=y
x+y=57
We can set these equations equal to each other to solve for the numbers by subtracting x from both sides of the second equation. Now the equations are:
y=-x+57 and x/2=y
Since both equations equal y, they are also equal to each other:
-x+57=x/2
First, multiply both sides by 2:
-2x+114=x
Add 2x to both sides.
114=3x
Divide both sides by 3.
38=x
One of the numbers is 38. Now, we can plug 38 in for x in either of the equations to solve for y:
(38)+y=57
Subtract 38 from both sides:
y=19
The two numbers are 38 and 19.
I hope this helps :)
Answer: 6t^2+11t+4 is the answer
