Answer:
A circle with center C has chords FB and DA which are equidistant from C.
Step-by-step explanation:
A chord is a straight line drawn from a point on the circumference of a circle to another point on the circumference, without passing through the center of the circle.
From the given question, a circle center C has two chords FB and DA that are equidistant from the center of the circle. The distant of FB from C is CG and the distance of DA from C is CE. But CG = CE, which implies that the two chords have equal distant from the center of the circle.
Therefore line CG from center C intersects FB at G, and line CE from center C intersects DA at E.
Answer:
B)
Step-by-step explanation:
None of the above.
The orthocenter is the point where the three altitudes meet. An altitude is the line from one vertex perpendicular to the opposite side.
8x+4y=-12
Put the equation in the form y=MX+b (m=slope)
4y=-8x-12
Y=-2x-3
The slope is -2
Hope this helps!
