The ticket price for the ice hockey match was £14.50. The price has increased by 7%.

Elliot spent $16.15 on ground beef at a grocery store. He purchased 3 and 2 over 5 pounds of ground beef. What is the price per

Andrej [43]

We want to know how much is the price per pound (or unit rate) of ground beef, given that we know the price for Elliot's purchase. We will see that each pound costs $4.75

So we know that (3 + 2/5) lb of ground beef costs $16.15, the cost of a single pound will be given by the quotient between the total cost and the amount purchased, then we need to solve:

$P =\frac{ \$ 16.15}{(3 + 2/5)lb}$

We can rewrite the denominator as:

(3 + 2/5)lb = (15/5 + 2/5)lb = (17/5) lb

Replacing that we get:

$P =\frac{ \$ 16.15}{(17/5)lb} = \frac{ \$ 16.15*5}{17lb} = \$4.75 \ per \ lb$

So each pound of ground beef costs $4.75

If you want to learn more about unit rates, you can read:

brainly.com/question/2375289

4 0

2 years ago

Solve x + 3y = 9<br> 3x – 3y = -13 (1 point)

Mariana [72]

Answer:

The values of x and y to the given equations are x=-1 and $y=\frac{10}{3}$

The solution is (-1, $\frac{10}{3}$ )

Step-by-step explanation:

Given equations are $x+3y=9\hfill (1)$

and $3x-3y=-13\hfill (2)$

to solve the given equations by elimination method :

Adding the given two equations (1) and (2) we get

$x+3y=9$

$3x-3y=-13$

_______________

4x=-4

$x=-\frac{4}{4}$

Therefore x=-1

Now substitute the value x=-1 in equation(1) we get

(-1)+3y=9

3y=9+1

$y=\frac{10}{3}$

Therefore the values of x and y to the given equations are x=-1 and $y=\frac{10}{3}$

The solution is (-1, $\frac{10}{3}$ )

8 0

3 years ago

This is for a Geometry-H class

crimeas [40]

Applying the linear angles theorem, the measures of the larger angles are: 130 degrees.

The measures of the smaller angles are 50 degrees

<h3>How to Apply the Linear Angles Theorem?</h3>

Based on the linear angles theorem, we have the following equation which we will use to find the value of y:

3y + 11 + 10y = 180

Add like terms

13y + 11 = 180

Subtract 11 from both sides

13y + 11 - 11 = 180 - 11

13y = 169

13y/13 = 169/13

y = 13

Plug in the value of y

3y + 11 = 3(13) + 11 = 50 degrees

10y = 10(13) = 130 degrees.

Therefore, applying the linear angles theorem, the measures of the larger angles are: 130 degrees.

The measures of the smaller angles are 50 degrees.

Learn more about the linear angles theorem on:

brainly.com/question/5598970

#SPJ1

6 0

1 year ago

A vector has an x-component of −24.5 units and a y-component of 31.5 units. Find the magnitude and direction of the vector.

jasenka [17]

we are given a vector

whose

x-component is -24.5

so, $v_x=-24.5$

y-component is 31.5

so, $v_y=31.5$

Magnitude:

we can use formula

$|v|=\sqrt{(v_x)^2+(v_y)^2}$

we can plug values

$|v|=\sqrt{(-24.5)^2+(31.5)^2}$

$|v|=39.90614$

Direction:

we can use direction formula

$\theta=tan^{-1}(\frac{v_y}{v_x})$

now, we can plug values

$\theta=tan^{-1}(\frac{31.5}{-24.5})$

$\theta=180-52.12$

$\theta=127.88$ ................Answer

8 0

3 years ago

HELP ASAP

dalvyx [7]

So,

All we have to do is multiply all three dimensions together.

First, convert all fractions into improper fractions.

$3 \frac{1}{5}--\ \textgreater \ \frac{16}{5}$

$1 \frac{3}{4} --\ \textgreater \ \frac{7}{4}$

$2 \frac{1}{4} --\ \textgreater \ \frac{9}{4}$

Now multiply the fractions together.

<span> $\frac{16}{5}*\frac{7}{4}*\frac{9}{4}= \frac{2*2*2*2*3*3*7}{2*2*2*2*5}$
</span>
$\frac{3*3*7}{5}--\ \textgreater \ \frac{63}{5}\ or\ 12 \frac{3}{5}\ ft.^3$

The correct option is C.

4 0

3 years ago