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4 years ago

The second shell in the ground state of atomic argon contains ________ electrons.

Physics

2 answers:

Charra [1.4K]4 years ago

5 0

The second shell in the ground state of atomic argon contains eight electrons.

mariarad [96]4 years ago

5 0

There are 18 electrons, so if you put them all into shells, it would be 2,8,8. That means there are 8 electrons in the second shell. Hope this helps :)

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A car which is traveling at a velocity of 1.6 m/s undergoes an acceleration of 9.2 m/s over a distance of 540 m. How fast is it

mixas84 [53]

Answer:

Vf = 99.7 m/s

Explanation:

In order to find the final velocity of the car, we will use the third equation of motion. The third equation of motion is given as follows:

$2as = V_{f}^{2} - V_{i}^{2}$

where,

a = acceleration of the car = 9.2 m/s²

s = distance traveled by the car = 540 m

Vf = Final Speed of the car = ?

Vi = Initial Speed of the car 1.6 m/s

$2(9.2\ m/s^{2})(540\ m) = (V_{f})^{2}-(1.6\ m/s)^{2}\\V_{f}^{2} = 9936\ m^{2}/s^{2} + 2.56\ m^{2}/s^{2}\\\\V_{f} = \sqrt{9938.56\ m^{2}/s^{2}}$

Vf = 99.7 m/s

8 0

3 years ago

A car is moving at 12 m per 2nd and has a mass of 600 kg what is the kinetic energy of the car

Brrunno [24]

Answer:

43,200 Joules

Explanation:

Kinetic energy can be found using the following formula:

$KE=\frac{1}{2}mv^2$

where m is the mass in kilograms and v is the velocity in m/s.

We know the mass is 600 kilograms, and the car is moving at 12 meters per second. Therefore the mass is 600 kilograms and the velocity is 12 m/s.

m=600

v=12

Substitute these values into the formula.

$KE=\frac{1}{2}600*12^2$

First, evaluate the exponent: 12^2. 12^2 is the same as 12*12, which is equal to 144.

$KE=\frac{1}{2}*600*144$

Multiply 600 and 144

$KE=\frac{1}{2}*86,400$

Multiply 1/2 and 86,400, or divide 86,400 by 2.

$KE=43,200$

Add appropriate units. Kinetic energy uses Joules, or J for units.

$KE=43,200 Joules$

The kinetic energy of the car is 43,200 Joules.

4 0

4 years ago

What makes an object stop, speed up, slow down or change direction? V2

ycow [4]

Your answer: Force

Explanation: The action from a force can cause an object to move or speed up, slow down, stop or change directions.

5 0

3 years ago

If a gun is sighted to hit targets that are at the same height as the gun and 75 m away at the same height, how low, as a positi

Vinvika [58]

Answer:

y=-1.66 m

Explanation:

We know that

Range R

$R=\dfrac{u^2sin2\theta }{g}$

Here given that

u= 275 m/s

R=75 m

Now by putting the values

$R=\dfrac{u^2sin2\theta }{g}$

$35=\dfrac{275^2sin2\theta }{9.81}$

θ=0.13°

Now horizontal component of velocity u will be u cosθ.

Horizontal component = 275 cos0.13 = 274.99 m/s

So the time required to cover 180 m in horizontal direction t

180 = 274.99 x t

t=0.65 sec

Now vertical component of velocity u will be u sinθ.

Horizontal component = 275 sin0.13 = 0.62 m/s

So now vertical displacement y will be

$y=u_yt-\dfrac{1}{2}gt^2$

$y=0.62 \times 0.65-\dfrac{1}{2}\times 9.81\times 0.65^2$

y=-1.66 m

5 0

3 years ago

In each of the following situations, a wave passes through an opening in an absorbing wall. Rank the situations in order from th

Delicious77 [7]

Answer:

A) geometric optics, B) geometric optics , c) geometric optics ,

e) geometric optics, f) geometric optics

Explanation:

For this exercise we must use the condition for interference and diffraction so that these phenomena are relevant the wavelength must be comparable to the gap spacing

λ> = a

Lam when the spacing is much greater than the wavelength, the description of geometric optics is more and more exact

let's analyze each situation

a) let's find the wavelength

v = λ f

λ= v / f

λ= 343/1000

λ = 0.343 m

0.343 << 1m

therefore the description of the geometric optics of

b) red light passes through the pupil of the eye

red light has a wavelength of 700 num or more, the lojo pupil has a maximum of 8 me

λ = 700 10⁻⁹ m = 7 10⁻⁷ m

a = 8 mm 10⁻³

longitudinal is much less therefore the geometric optics is correct

c) luz azul lam = 450 nm = 450 10⁻⁹ m = 4.5 10⁻⁷ m

again the wavelength is much less than the diameter of the pupil, for which the description with the optics is generally sufficient

d) a radio A transmits up to a maximum of f = 1400 Khz = 1,400 10⁶ Hz

let's find the wavelength

c = λf

λ = c / f

λ= 3 108 / 1,400 106

λ= 2.14 102 m

in this case the wavelength is greater than the width of the gate, so the description of diffraction should be used to explain the phenomenon

e) X-rays have wavelength lam = 10-10 m

the separation of the elbow bones is of the order of a few millimeters, for local the wavelength is much less than the separation, therefore with the relations of geometric optics it is sufficient

5 0

3 years ago