Answer:
T = 92.8 min
Explanation:
Given:
The altitude of the International Space Station t minutes after its perigee (closest point), in kilometers, is given by:

Find:
- How long does the International Space Station take to orbit the earth? Give an exact answer.
Solution:
- Using the the expression given we can extract the angular speed of the International Space Station orbit:

- Where the coefficient of t is angular speed of orbit w = 2*p / 92.8
- We know that the relation between angular speed w and time period T of an orbit is related by:
T = 2*p / w
T = 2*p / (2*p / 92.8)
Hence, T = 92.8 min
Answer:
68 °F, 293.15 K
Explanation:
Fahrenheit, Kelvin and Celsius are the different scales of temperature in which temperature is measured.
Given : T = 20°C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
<u>T = (20 + 273.15) K = 293.15 K </u>
The conversion of T( °C) to T(F) is shown below:
T (°F) = (T (°C) × 9/5) + 32
So,
<u>T (°F) = (20 × 9/5) + 32 = 68 °F</u>
Answer:
e=mc2 made to relate mass with energy . bcoz energy can neither b created nor b destroyed