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Dafna1 [17]
3 years ago
10

Five hundred joules of heat are added to a closed system. The initial internal energy of the system is 87 J, and the final inter

nal energy is 134 J. How much work is being done by the system?
Physics
2 answers:
stiks02 [169]3 years ago
8 0

Answer: W = 453J

Explanation: using first law of thermodynamics

∆U = Q - W

Where

Q= heat added

W = work done

∆U = internal energy

Also ∆U = Uf - UI

=134 -87

= 47J

Therefore work done will be

W = Q- ∆U

= 500 - 47

= 453J

Aleonysh [2.5K]3 years ago
5 0

We can solve the problem by using the first law of thermodynamics:

\Delta U= Q-W

where

\Delta U is the variation of internal energy of the system

Q is the heat added to the system

W is the work done by the system

In this problem, the variation of internal energy of the system is

\Delta U=U_f-U_i=134 J-87 J=47 J

While the heat added to the system is

Q=500 J

therefore, the work done by the system is

W=Q-\Delta U=500 J-47 J=453 J

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Answer with Explanation:

a. Option d is true.

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7 0
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T/F is the following statement true or false? a person with antisocial personality disorder typically must be older than the age
sukhopar [10]

A person with antisocial personality disorder typically must be older than the age of 18 years and have shown some evidence of a conduct disorder. This is true statement.

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3 0
1 year ago
a ball on a string makes 30.0 revolutions in 14.4s, in a circle of radius 0.340m. what is its period.(unit=s)
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Answer:

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t = 0.480 s

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7 0
3 years ago
What does it mean when work is positive?
Degger [83]

Answer:

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Explanation:

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You can also appreciate this from the work equation

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bold indicate vector

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7 0
3 years ago
A 7.1 resistor and a 4.8 resistor are connected in series with a battery. the potential difference across the 4.8 resistor is me
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4 0
3 years ago
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