Five hundred joules of heat are added to a closed system. The initial internal energy of the system is 87 J, and the final inter
2 answers:
We can solve the problem by using the first law of thermodynamics:
where
is the variation of internal energy of the system
Q is the heat added to the system
W is the work done by the system
In this problem, the variation of internal energy of the system is
While the heat added to the system is
therefore, the work done by the system is
You might be interested in
Answer:
(A) 6174J, 0J.
(B) 7374J
(C) 7374J
Explanation:
See the attachment below for the calculation.
The princi6of conservation of energy has been used.
E = K1 + U1 = K2 + U2
Where E = total mechanical energy.
Taking the bottom as reference, and h =0 and as a result U2 = mg(0) = 0J.
The complete solution to the problem can be found in the attachment below.
