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Dafna1 [17]
3 years ago
10

Five hundred joules of heat are added to a closed system. The initial internal energy of the system is 87 J, and the final inter

nal energy is 134 J. How much work is being done by the system?
Physics
2 answers:
stiks02 [169]3 years ago
8 0

Answer: W = 453J

Explanation: using first law of thermodynamics

∆U = Q - W

Where

Q= heat added

W = work done

∆U = internal energy

Also ∆U = Uf - UI

=134 -87

= 47J

Therefore work done will be

W = Q- ∆U

= 500 - 47

= 453J

Aleonysh [2.5K]3 years ago
5 0

We can solve the problem by using the first law of thermodynamics:

\Delta U= Q-W

where

\Delta U is the variation of internal energy of the system

Q is the heat added to the system

W is the work done by the system

In this problem, the variation of internal energy of the system is

\Delta U=U_f-U_i=134 J-87 J=47 J

While the heat added to the system is

Q=500 J

therefore, the work done by the system is

W=Q-\Delta U=500 J-47 J=453 J

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