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3 years ago

The first model of the atom was developed through what?

Physics

2 answers:

Karolina [17]3 years ago

6 0

Answer:

scientific experimentation and data analysis with water vapor and gases.

Explanation:

Don't listen to daylin55555 she is wrong. I took the test.

Dennis_Churaev [7]3 years ago

5 0

Democritus Introduces the Atom
He thought that a point would be reached where matter could not be cut into still smaller pieces. He called these "uncuttable" pieces atomos. This is where the modern term atom comes from. Democritus first introduced the idea of the atom almost 2500 years ago.

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A 0.0220 kg bullet moving horizontally at 400 m/s embeds itself into an initially stationary 0.500 kg block. (a) What is their v

nevsk [136]

Answer:

a) 16.86 m/s.

b) 15.40 m/s

c) 3.175 m/s

Explanation:

let pi be the initial momentum of the system, pf be the final momentum of the system, m1 be the mass of the bullet and V1 be the intial velocity of the bullet, m2 be the mass of the block and V2 be the intial velocity of the block

a) from the conservation of linear momentum:

pi = pf

m1×(V1)i + m2×(V2)i = Vf×(m1 + m2)

(0.0220)×(400) + (0.500)×(0) = Vf(0.0220 + 0.500)

8.8 = 0.522×Vf

Vf = 16.86 m/s

Therefore, the bullet-embedded block system will be moving with a speed of 16.86 m/s.

b) let Vf be the final velocity of the bullet-embedded block system, Wf be the work done by friction on the system, Vi be the initial velocity that the bullet-embedded block system initially moves with.

the total work done on the system is given by:

Wtot = Δk = kf - ki

Wf = 1/2×m×(Vi)^2 - 1/2×m×(Vf)^2

f×ΔxΔcos(Ф) = 1/2×m×(Vi)^2 - 1/2×m×(Vf)^2

m×Δx×g×μ×(-1) = 1/2×m×(Vi)^2 - 1/2×m×(Vf)^2

m×g×Δx×μ = 1/2(Vi)^2 - 1/2(Vf)^2

1/2(0.0220 + 0.500)(Vf)^2 = 1/2(0.0220 + 0.500)(16.86)^2 - (0.0220 + 0.500)×(9.8)×(8)×(0.30)

(0.261)(Vf)^2 = 86.469

(Vf)^2 = 237.2196

Vf = 15.40 m/s

Therefore, bullet-embedded block system will have a speed of 15.40 m/s after sliding of the friction surface.

c) let Vf be the speed of the bullet-embedded before hitting the block, Vi be the initial velocity of the block and V be the velocity of the bullet-embedded block and block system.

M×Vf + m×Vi = (m + M)×V

(0.0200 + 0.50)×(15.40) + (2)×(0) = (0.022 + 0.50 + 2)×V

8.008 = 2.522×V

V = 3.175 m/s

Therefore, the bullet-embedded block and block system will be moving at a speed of 3.175 m/s.

5 0

3 years ago

A ball rolls 8m in 2 sec. What is the ball's speed?

Setler [38]

Answer:

16 m/s , hope this helps.

6 0

3 years ago

Which description properly describes the plant structures involved in photosynthesis?

raketka [301]

Answer:

Explanation:

Stomata take in carbon dioxide (i think they realease oxygen too), Phloem transports the glucose throughout the plant, Xylem transports the water and minerals from the roots. If you want me to explain more I can

3 0

3 years ago

Read 2 more answers

A baseball team is practicing throwing balls vertically upward to test their throwing arms. A player manages to throw a ball tha

Nitella [24]

We can solve this problem using the law of conservation of energy.
This law states that energy in a closed system must stay same.
That means that the energy of a ball leaving the hand and the energy of a ball when it reaches its maximum height must be the same.
The energy of a ball leaving the players hand is kinetic energy:
$E_k=\frac{mv^2}{2}$
The energy when the ball reaches its maximum height ( and has zero velocity) is potential energy in a gravitational field:
$E_p=mgh$
As said before these energies must be the same, and that allows us to find the initial speed:
$E_k=E_p\\
\frac{mv^2}{2}=mgh\\
v^2=2gh\\
v=\sqrt{2gh}$
When we plug in all the number we get that $v=14\frac{m}{s}$

7 0

3 years ago

Need help on this one please

mamaluj [8]

The atomic number is a neutron

3 0

3 years ago