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Anna [14]
3 years ago
13

Which pair of substances would most likely result in the production of a solid when reacting with a base? litmus and phenolphtha

lein soluble metal salt and carbon dioxide acids and water hydrogen ions and soaps
Chemistry
2 answers:
svet-max [94.6K]3 years ago
8 0
<h3><u>Answer;</u></h3>

<em>Soluble metal salt and carbon dioxide</em>

<h3><u>Explanation;</u></h3>

Both <u><em>soluble metal salt and carbon dioxide</em></u> may react with a base to form a solid or what we call a precipitate.

  • For instance when <u><em>carbon dioxide is bubbled through a solution of calcium hydroxide, it results to the formation or precipitate calcium carbonate.</em></u>

<em>Ca(OH)₂(aq) + CO₂(g) → CaCO₃(s) + H₂O(l)</em>

  • For the case of a soluble metal salt; an example is calcium nitrate, which is <em><u> a soluble metal salt, when reacted with a base like sodium hydroxide, it results to the formation of a solid calcium hydroxide</u></em> and sodium nitrate, a reaction called precipitation reaction.

<em>Ca(NO₃)₂(aq) + NaOH (aq)→ Ca(OH)₂(s) + NaNO₃(aq)</em>

iren2701 [21]3 years ago
6 0

Answer:

It is B on e2020

Explanation:

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Acetanilide has a solubility of 1.00 g/185 ml in 25 oc water and 1.00 g/20 ml in 100 oc water. what is the minimum volume of wat
Likurg_2 [28]

In the crystallization process the solid compound is dissolved in the solvent at elevated temperature and the crystallize product obtained by slow cooling of the  solution. Here the solubility of acetanilide at 100°C is 1g per 20mL of water. Thus to dissolve 500mg of acetanilide at high temperature that is 100°C we need 10mL of water.

Now at 25°C after the re-crystallization there will be some amount of dissolve acetanilide. Which can be calculated as- 185mL of water is needed to dissolve 1g or 1000mg of acetanilide at 25°C. Thus in 10mL of water there will be \frac{10X1000}{185}=54.05gmg of acetanilide.    

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How many molecules of excess reactant remain after the reaction is complete?
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Please help me, I really don't want to fail but I don't know how to do this
Brrunno [24]

Answer:

A)

<u>4, 7, 4, 6</u>

B)

<u>12 moles</u>

Explanation:

NH_{3}(g) + O_{2}(g) \: → NO_{2} + H_{2}O(g)

__↑______↑

8.00 mol | 14.00 mol

________________

NH_{3}(g) + O_{2}(g) \: → NO_{2} + H_{2}O(g)

You can turn this into a system of variables which are solvable.

To do this, create variables for the coefficients of each compound in the reaction respectively.

a(NH_{3}(g)) + b(O_{2}(g)) → \\c(NO_{2}) + d(H_{2}O(g))

Because to be balanced, the count of atoms in each element of the compound correspond to the coefficient of the variable in that compound so that the count of the left (reactant) side is set equal to the right (product) side.

a corresponds to the coefficient of the first compound, b corresponds to the coefficient of the second compound, c corresponds to the coefficient of the third compound, and d corresponds to the coefficient of the fourth compound.

(Reactant = Product)

Reactant: 1a [N] Product: 1c.

Reactant: 3a [H] Product: 2d.

Reactant: 2b [O] Product: 2c + 1d.

Thus the system is:

1a = 1c

3a = 2d

2b = 2c + 1d.

Then just use the substitution methods to solve.

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