Question

How many elements of unsaturation are implied by the molecular formula c6h12?

Answer 1

(2C+2-H-X+N)/2
(2*6+2-12-0+0)/2
1 UNSATURATION

Answer 2

There is $\boxed{{\text{one}}}$ element of unsaturation that is implied by the molecular formula ${{\text{C}}_{\text{6}}}{{\text{H}}_{{\text{12}}}}$.

Further Explanation:

Hydrocarbons are organic compounds that are composed of hydrogen and carbon only. Aromatic hydrocarbons, alkanes, cycloalkanes are different types of hydrocarbons.

Types of hydrocarbons:

1. Saturated hydrocarbons

These are the simplest type of hydrocarbons. These are composed of only single bonds and therefore called saturated hydrocarbons. The general formula of saturated hydrocarbons is ${{\text{C}}_n}{{\text{H}}_{2n + 2}}$, where n is the number of carbon atoms. Methane, butane, hexane, and propane are some examples of saturated hydrocarbons.

2. Unsaturated hydrocarbons

These have one or more multiple bonds in them. Hydrocarbons consisting of double bonds are called alkenes while those comprising of triple bonds are called alkynes. The general formula for alkenes is ${{\text{C}}_n}{{\text{H}}_{2n}}$, while that of alkynes is ${{\text{C}}_n}{{\text{H}}_{2n - 2}}$, where n is the number of carbon atoms.

The formula to calculate the element of unsaturation is as follows:

${\text{Element of unsaturation}}=\dfrac{{\left( {2{\text{C}} + {\text{2}} - {\text{H}} - {\text{X}} + {\text{N}}} \right)}}{2}$                                        …… (1)

Here,

C is the number of carbons.

H is the number of hydrogens.

X is the number of halogens.

N is the number of nitrogens.

The molecular formula of the given compound is ${{\text{C}}_6}{{\text{H}}_{12}}$. So it has 6 carbon atoms and 12 hydrogen atoms in it.

Substitute 6 for C, 12 for H, 0 for X and 0 for N in equation (1).

$\begin{aligned}{\text{Element of unsaturation}}&=\frac{{\left( {2\left( {\text{6}} \right) + {\text{2}} - {\text{12}} - {\text{0}} + {\text{0}}} \right)}}{2}\\&={1}\end{aligned}$

Therefore there is only one element of unsaturation in ${{\text{C}}_6}{{\text{H}}_{12}}$. This indicates either the presence of a double bond or a ring in the given compound.

Learn more:

1. What is the empirical formula of the compound? brainly.com/question/6126420

2. Write the name of the hydrocarbon: brainly.com/question/3551546

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Hydrocarbons

Keywords: hydrocarbon, saturated, unsaturated, alkene, alkyne, CnH2n+2, CnH2n, CnH2n-2, element of unsaturation, 1, .ring, double bond.