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Ulleksa [173]
2 years ago
6

How many grams of a stock solution that is 87.5 percent H2SO4 by mass would be needed to make 275 grams of a 55.0 percent by mas

s solution? Show all of the work needed to solve this problem.
Chemistry
2 answers:
cricket20 [7]2 years ago
7 0
Take a look into this beautiful part and you will get your answer
<span>275 grams of a 55 per cent solution contains 0.55* 275 grams of pure H2SO4. We need to find the mass of 87.5 per cent solution which contains 0.55*275 grams H2SO4 this is (0.55* 275) / 0.875 grams. In that way you will have your answer. I hope this can help</span>
levacccp [35]2 years ago
7 0

The mass of sulfuric acid in the required solution is 55g per 100g of solution

We need to make total of 275 grams of solution of concentration 55%

So we need following amount of sulfuric acid in the solution

55% of 275  grams = 0.55 X 275 = 151.25 grams

Now we have a stock solution of sulfuric acid 87.5% (w/w)

It means in every 100g of solution 87.5g of sulfuric acid

We need 151.25 grams of sulfuric acid

87.5g of sulfuric acid will be obtained from 100g of stock solution

1g of sulfuric acid will be obtained from 100/87.5g of stock solution

151.25g of sulfuric acid will be obtained from = \frac{100X151.25}{87.5}=172.85g

Hence we will take 172.85 grams of stock solution to prepare 55% sulfuric acid solution of mass 275g

Rest we will take water.

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iVinArrow [24]
When you heat up most substances it gives them more Kinetic energy and the substance becomes less arranged in an ordered state, further apart and move faster. therefore the answer is the first: They gain a higher average kinetic energy

Hope that helps :)
7 0
3 years ago
By what factor will the kinetic energy change if the speed of the baseball is decreased to 54.8 mi/h? Express your answer as an
Serggg [28]

Answer:

The Kinetic Energy is approximately 3 times decreased

Explanation:

A baseball weighs 5.13 oz.  

a)What is the kinetic energy, in joules, of this baseball when it is thrown by a major league pitcher at 95.o mi/h?  

b) By what factor will the kinetic energy change if the speed of the baseball is decreased to 54.8 mi/h? Express your answer as an integer.

Kinetic Energy (KE)=0.5×mass×velocity ^ 2

Kinetic Energy (KE)=0.5×mass × velocity ^ 2

Joules = kg×m^2/s^2

1 mile = 1609.344 meters

1 hour = 3600 sec

1 Oz = 28.34952 g = 0.02834952 kg

a) KE=0.5×m×v^2

=0.5×(5.13 oz × 0.02834952 kg/1 ounce)×(95 miles/h × 1609.344 m/1 mile × 1 hr/3600 s)^2

=130.761 kg×m^2/s^2 = 130.761 Joules

b) KE=0.5×m×v^2

=0.5×(5.13 oz × 0.02834952 kg/1 ounce)×(54.8 miles/h × 1609.344 m/1 mile × 1 hr/3600 s)^2

=43.51028 kg×m^2/s^2 = 43.51028 Joules

= 130.761 / 43.51028 = 3.00528,  

As such the Kinetic Energy is approximately 3 times decreased

4 0
3 years ago
What is the balanced form of the chemical equation shown below?
mihalych1998 [28]

The balanced form of the chemical equation shown is N₂(g) + 3H₂(g) → 2NH3(g) (option A).

<h3>What is a balanced equation?</h3>

A chemical equation is said to be balanced when the number of atoms of each element on both sides of the equation is the same.

According to this question, the chemical equation between nitrogen and hydrogen is given as follows: N₂(g) + H₂(g) → NH3(g)

The balanced form of the chemical equation shown is N₂(g) + 3H₂(g) → 2NH3(g).

Learn more about balanced equation at: brainly.com/question/7181548

#SPJ1

5 0
2 years ago
How many electrons can be held in the third orbital?.
Evgen [1.6K]
32 electrons. as the orbitals get father away from the nucleus, they hold more electrons.
6 0
2 years ago
Read 2 more answers
Please balance the equation C7H16 + CoF3 = C7F16 + HF +CoF2<br> with solutions
Andrei [34K]

Answer:

C₇H₁₆ + 32CoF₃ —> C₇F₁₆ + 16HF + 32CoF₂

Explanation:

C₇H₁₆ + CoF₃ —> C₇F₁₆ + HF + CoF₂

The above equation can be balance as illustrated below:

C₇H₁₆ + CoF₃ —> C₇F₁₆ + HF + CoF₂

There are 16 atoms of H on the left side and 1 atom on the right side. It can be balance by writing 16 before HF as shown below:

C₇H₁₆ + CoF₃ —> C₇F₁₆ + 16HF + CoF₂

There are 3 atoms of F on the left side and a total of 34 atoms on the right side. It can be balance by writing 32 before CoF₃ and 32 before CoF₂ as shown below:

C₇H₁₆ + 32CoF₃ —> C₇F₁₆ + 16HF + 32CoF₂

Now, the equation is balanced.

3 0
2 years ago
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