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nexus9112 [7]
3 years ago
13

Convert 250.0F into C

Chemistry
2 answers:
TiliK225 [7]3 years ago
8 0
121.111 when converted
Irina-Kira [14]3 years ago
3 0
250^oF is equal to 120 c

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Why is the sun up sometimes but not other times?
MatroZZZ [7]

Answer: The Sun appears to move across the sky because the Earth rotates on its axis. ... When where you are is pointed toward the Sun, it is day. Then the Earth rotates you away from the Sun, and it is night.

Explanation:

6 0
3 years ago
Which of the following possess the greatest concentration of hydroxide ions?
jek_recluse [69]

Answer : The correct option is (d) a solution of 0.10 M NaOH

Explanation :

<u>(a) a solution of pH 3.0</u>

First we have to calculate the pOH.

pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-3.0=11

Now we have to calculate the OH^- concentration.

pOH=-\log [OH^-]

11=-\log [OH^-]

[OH^-]=1.0\times 10^{-11}M

Thus, the OH^- concentration is, 1.0\times 10^{-11}M

<u>(b) a solution of 0.10 M NH_3</u>

As we know that 1 mole of NH_3 is a weak base. So, in a solution it will not dissociates completely.

So, the OH^- concentration will be less than 0.10 M

<u>(c) a solution with a pOH of 12.</u>

We have to calculate the OH^- concentration.

pOH=-\log [OH^-]

12=-\log [OH^-]

[OH^-]=1.0\times 10^{-12}M

Thus, the OH^- concentration is, 1.0\times 10^{-12}M

<u>(d) a solution of 0.10 M NaOH</u>

As we know that NaOH is a strong base. So, it dissociates to give Na^+ ion and OH^- ion.

So, 0.10 M of NaOH in a solution dissociates to give 0.10 M of Na^+ ion and 0.10 M of OH^- ion.

Thus, the OH^- concentration is, 0.10 M

<u>(e) a 1\times 10^{-4}M solution of HNO_2</u>

As we know that 1 mole of HNO_2 in a solution dissociates to give 1 mole of H^+ ion and 1 mole of NO_2^- ion.

So, 1\times 10^{-4}M of HNO_2 in a solution dissociates to give 1\times 10^{-4}M of H^+ ion and 1\times 10^{-4}M of NO_2^- ion.

The concentration of H^+ ion is 1\times 10^{-4}M

First we have to calculate the pH.

pH=-\log [H^+]

pH=-\log (1.0\times 10^{-4})

pH=4

Now we have to calculate the pOH.

pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-4=10

Now we have to calculate the OH^- concentration.

pOH=-\log [OH^-]

10=-\log [OH^-]

[OH^-]=1.0\times 10^{-10}M

Thus, the OH^- concentration is, 1.0\times 10^{-10}M

From this we conclude that, a solution of 0.10 M NaOH possess the greatest concentration of hydroxide ions.

Hence, the correct option is (d)

3 0
3 years ago
How many moles of nitrogen, N, are in 61.0 g of nitrous oxide, N2O?
Oksana_A [137]

Answer:

2.77 mol N

Explanation:

M(N2O) = 2*14 + 16 = 44 g/mol

61.0 g * 1 mol/44g = (61/44) mol N2O

                       N2O ---- 2N

                    1 mol         2 mol

            (61/44) mol        x mol

x = (61/44)*2/1 = 2.77 mol N

4 0
3 years ago
If fluorine gas (F₂) occupies a volume of 45.5 L at a pressure of 850
pshichka [43]

Taking into account about the ideal gas law, the mass of fluorine gas is 63.2244 grams.

<h3>What is ideal gas law</h3>

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

where:

  • P is the gas pressure.
  • V is the volume that occupies.
  • T is its temperature. The universal constant of ideal gases R has the same value for all gaseous substances.
  • R is the ideal gas constant.
  • n is the number of moles of the gas.

<h3>Definition of molar mass</h3>

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

<h3>Mass of fluorine gas</h3>

In this case, you know:

  • P= 850 mmHg= 1.11842 atm (being 1 mmHg= 0.00131579 atm)
  • V= 45.5 L
  • T =100 °C= 373 K (being 0°C= 273 K)
  • R= 0.082 \frac{atm L}{mol K}
  • n= ?

Replacing in the ideal gas law:

1.11842 atm ×45.5 L = n×0.082 \frac{atm L}{mol K}× 373 K

Solving:

n= (1.11842 atm ×45.5 L)÷ (0.082 \frac{atm L}{mol K}× 373 K)

<u><em>n= 1.6638 moles</em></u>

The molar mass of F₂ is 38 g/mole. Then you can apply the folowing rule of three: If by definition of molar mass 1 mole of the compound contains 38 grams, 1.6638 moles of the compound contains how much mass?

mass= \frac{1.6638 molesx38 grams}{1 mole}

<u><em>mass= 63.2244 grams</em></u>

Finally, the mass of fluorine gas is 63.2244 grams.

Learn more about

the ideal gas law:

brainly.com/question/4147359

molar mass:

brainly.com/question/5216907

brainly.com/question/11209783

brainly.com/question/7132033

brainly.com/question/17249726

#SPJ1

7 0
1 year ago
True or False: As the ball rises from point 1 to point 3, it slows down
quester [9]
True, it would slow down.
7 0
3 years ago
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