Question

What is the temperature of 4.5 moles of a gas that occupies 50. mL at 1.35 atm?

Answer 1

Answer:

$T = 0.182$ Kelvin

Explanation:

As we know that

$PV = nRT$

Where P is the pressure in atmospheric pressure

T is the temperature in Kelvin  

R is the gas constant  

V is the volume in liters

$R = 0.08206$

Substituting the given values in above equation, we get -

$1.35 * \frac{50}{1000}= 4.5 * 0.08206* T$

On rearranging, we get

$T = \frac{1.35*50}{1000*0.08206*4.5}$

$T = 0.182$ Kelvin