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1 year ago

PLEASE HELP!!! ILL MARK A HIGH POINT COUNT, GIVE BRAINLIEST, FIVE STARS, AND GIVE THANKS TO WHOEVER ANSWERS CORRECTLY!!!!

1 answer:

3 0

Each letter of the alphabet is worth two times as much as the one before it, implying that the value of each letter rises in mathematical progression. The formula for finding the nth term of an arithmetic progression would be used. I am written as

a + (n - 1)d = Tn

Where

The number of terms in the arithmetic sequence is represented by n.

The common difference of the terms in the arithmetic sequence is represented by d.

The first term of the arithmetic sequence is represented by a.

Tn stands for the nth word.

Based on the facts provided,

n = 26 characters1 Equals a

3 minus 1 equals 2 (difference between 2 letters)

Therefore,

1 + (26 - 1)2 = T26

51 = T26

The formula for calculating the sum of an arithmetic sequence's n terms

is as follows:

[2a + (n - 1)d] Sn = n/2

As a result, S26 is the sum of the first 26 terms.

S26 = 20/2[2 1 + (26 - 1)2] S26 = 20/2

[2 + 50] S26 =

676 = S26 = 13 52

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A jar made of 3/16-inch-thick glass has an inside radius of 3.00 inches and a total height of 6.00 inches (including the bottom

Nady [450]

Answer:

a) 0.012ft³

b)2.09 lb

c)0.791 lb

d) 0.012ft³

e) 6 inches

Step-by-step explanation:

a) To determine the volume of the shell of the jar we must determine the volume of the hollow cylinder:

$V=3.1416\cdot{h}\cdot{(R^2-r^2)$

Where r is the inside radius and R the outer radius.

$V=3.1416\cdot{6}\cdot{(3.1875^2-3^2)=21.87$

convert to cubic ft:

$=21.87\cdot{0.0005787}=0.01266$

The volume of the glass shell is 0.012 ft³

b) The weight of the cylinder can be determined because we have the volume and the density. Weight is defined as the product of volume and density:

$M=p\cdot{v}=165\cdot{0.01266}=2.09$

The weight of the jar is 2.09 lb

c) The displacement of water is just the density of water mutliplied by the volume of the jar:#

$=0.01266\cdot{62.5}=0.79$

0.791 lb of water will be displaced.

d) The volume of the water displaced is:

[tex]=0.791/62.5=0.01266

e) The jar will be fully submerged because the density of the jar is larger than water.

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3 years ago

3/2-x + 5/4-2x - 1/x-2 =4

dimaraw [331]

Is there like a question???

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2 years ago

Jane is making a suit which requires 2 5⁄8 yards for the jacket and 1 3⁄4 yards for the skirt. What's the total amount of materi

Ann [662]

The answer is B. 4 3⁄8 yards. The amount of material needed for the jacket is: x = 2 5/8 yd = 2 + 5/8 = 16/8 + 5/8 = (16+5)/8 = 21/8 yd. The amount of material needed for the skirt is: y = 1 3/4 yd = 1 + 3/4 = 4/4 + 3/4 = (4+3)/4 = 7/4 yd. The total amount of material Jane needs is: x + y = 21/8 + 7/4 = 21/8 + 14/8 = (21+14)/8 = 35/8 = (32+3)/8 = 32/8 + 3/8 = 4 + 3/8 = 4 3/8 yd.

7 0

3 years ago

In a survey of adults aged 57 through 85 years, it was found that 86.6% of them used at least one prescription medication. Com

OleMash [197]

Answer:

a) 272 used at least one prescription medication.

b) The 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication is (85.6%, 87.6%).

Step-by-step explanation:

Question a:

86.6% out of 3149, so:

0.866*3149 = 2727.

272 used at least one prescription medication.

Question b:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 3149, \pi = 0.866$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a p-value of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.866 - 1.645\sqrt{\frac{0.866*0.134}{3149}} = 0.856$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.866 + 1.645\sqrt{\frac{0.866*0.134}{3149}} = 0.876$

For the percentage:

0.856*100% = 85.6%

0.876*100% = 87.6%.

The 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication is (85.6%, 87.6%).

7 0

2 years ago

Please help ASAP !!!

Deffense [45]

Your answer is A !!!

Please mark BRAINLEST

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2 years ago