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Oduvanchick [21]
1 year ago
15

tex-formula">
find expressions for f(n+3) and f(n+1)
hence find the value of k such that f(n+3)-f(n+1)= kf(n) where k ∈ N
Mathematics
1 answer:
andrezito [222]1 year ago
4 0

Answer:

24(f(n))

Step-by-step explanation:

f(n+3) = 3^{n+3}\\f(n+1) = 3^{n+1}

so

f(n+3) - f(n+1) = 3^{n+3} - 3^{n+1}

= 27(3^n) - 3(3^n)

= 24(3^n)

= 24(f(n))

hope this helped! :)

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