Obtuse: b^2 + c^2 > a^2
Right: b^2 + c^2 = a^2
Acute: b^2 + c^2 < a^2
A^2 + B^2 + c^2 - 2bc*cosA
As (A), is an Obtuse cos A is Negative say 2bccosA = - k then;
a^2 = b^2 + c^2 + k
a^2 > b^2 + c^2
So, your Answer would be (B)
Hope this helps!!.!
Answer:
The property that I would use is that however many decimal points are in the equation is the number of decimal places in the answer
Step-by-step explanation:
Answer:
Option B
Step-by-step explanation:
Complex roots occur as conjugate pairs so the third root is -3 - i ( note that the sign changes from + to -).
So in factor form we have:-
(x - 2)(x - (-3 + i))(x - (-3 - i)) = 0 Let's expand the last 2 factors first:-
(x - (-3 + i))(x - (-3 - i))
= (x + 3 - i)(x + 3 + i)
= x^2 + 3x +ix + 3x + 9 + 3i - ix - 3i - i^2
= x^2 + 6x + 9 - (-1)
= x^2 + 6x + 10
Now multiplying by (x - 2):-
(x - 2)(x^2 + 6x + 10) = 0
x^3 + 6x^2 + 10x - 2x^2 - 12x - 20 = 0
x^3 + 4x^2 - 2x - 20 = 0 (answer)
Option B
Answer:
y=1/2x-5
Step-by-step explanation:
We have slope so we just need to find the y intercept.
slope intercept formula is
y=mx+b
(m) is slope
(b) is y int
y=1/2x+b
now apply our given x and y values (4 & -3)
-3=1/2(4)+b
simplify
-3=2+b
subtract 2 from each side
-5=b
put that into our equation
y=1/2x-5
Answer: Divide by -2
Step-by-step explanation: In an equation where you have ab = n, then you divide by a. So then you get b = n/a.
If my answer was helpful, please mark it as brainliest.
