Question

A doppler radar sends a pulse at 6.00x10^9 hz. it reflects off some clouds, and returns to the radar 672 hz higher. what is the speed of the clouds?

Answer 1

Answer:

v-rel = 16.8

Make sure to read the explaination so you can solve it yourself!

Explanation:

I had this same question on Acellus, here is how I answered it:

Equation being used:   Δf = 2*fο*vrel/c

( this equation can be found in the  bottom of the lesson manual in the help tab)

Where,

Δf = change in frequency; 672

fο = frequency before being doppler shifted; 6.00 * 10^9

vrel = relative velocity; unknown

c = speed of light; 3.00 * 10^8

Now that we have written the numbers we know down, we must rearrange the equation for the velocity (vrel)

Starting Equation:

Δf = 2*fο*vrel/c

Multiply by c, then divide by 2fo to isolate vrel.

This will leave us with the equation:

Δfc/2fo, now we plug in the numbers

(672 * (3*10^8)) / (2* (6.00*10^9))

Once we plug this into the calculator, you should get

16.8

I hope this helped you, Wawawewa!