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Eduardwww [97]
3 years ago
8

What are three ways heat is transfered

Chemistry
2 answers:
zaharov [31]3 years ago
8 0

Answer:

Conduction convection and radiation

Explanation:

Look at pic.

Gre4nikov [31]3 years ago
6 0

Answer:

Conduction, Convection and Radiation

Explanation:

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What volume is occupied by 2.1 g O2 at 13 C and a pressure of 0.1atm?
Monica [59]

PV=nRT

n = mole = 2.1 g : 32 g/mole = 0.065

T = 13 + 273 = 286 K

V = nRT/P

V = (0.065 x 0.08205 x  286)/0.1

V = 15.253 L

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2 years ago
What elements are made from the body
Iteru [2.4K]

Answer:

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Searches related to If 0.75 grams of iron (Fe) react according to the following reaction, how many grams of copper (Cu) will be
jolli1 [7]

Answer:

0.83 g

Explanation:

Step 1: Write the balanced equation

Fe + CuSO₄ ⇒ Cu + FeSO₄

Step 2: Calculate the moles corresponding to 0.75 g of Fe

The molar mass of Fe is 55.85 g/mol.

0.75g \times \frac{1mol}{55.85g} = 0.013 mol

Step 3: Calculate the moles of Cu produced from 0.013 moles of Fe

The molar ratio of Fe to Cu is 1:1. The moles of Cu produced are 1/1 × 0.013 mol = 0.013 mol.

Step 4: Calculate the mass corresponding to 0.013 moles of Cu

The molar mass of Cu is 63.55 g/mol.

0.013mol \times \frac{63.55g}{mol} = 0.83 g

4 0
4 years ago
Read 2 more answers
2) Show the calculation of Kc for the following reaction if an initial reaction mixture of 0.800 mole of CO and 2.40 mole of H2
nadezda [96]

Answer:

Kc = 3.90

Explanation:

CO reacts with H_2 to form CH_4 and H_2O. balanced reaction is:

CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g)  +  H_2O(g)

No. of moles of CO = 0.800 mol

No. of moles of H_2 = 2.40 mol

Volume = 8.00 L

Concentration = \frac{Moles}{Volume\ in\ L}

Concentration of CO = \frac{0.800}{8.00} = 0.100\ mol/L

Concentration of H_2 = \frac{2.40}{8.00} = 0.300\ mol/L

                 CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g)  +  H_2O(g)

Initial            0.100      0.300             0   0

equi.            0.100 -x    0.300 - 3x     x    x

It is given that,

at equilibrium H_2O (x) = 0.309/8.00 = 0.0386 M

So, at equilibrium CO = 0.100 - 0.0386 = 0.0614 M

At equilibrium H_2 = 0.300 - 0.0386 × 3 = 0.184 M

At equilibrium CH_4 = 0.0386 M

Kc=\frac{[H_2O][CH_4]}{[CO][H_2]^3}

Kc=\frac{0.0386 \times 0.0386}{(0.184)^3 \times 0.0614} =3.90

8 0
4 years ago
What type of cleaner is appropriate for grease that has built up on appliances?
evablogger [386]
Baking soda and dish soap! youre welcome

6 0
4 years ago
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