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Oliga [24]
3 years ago
10

Magnesium bromide is a binary ionic compound. From its formula, MgBr2, how do you know that

Chemistry
2 answers:
Scilla [17]3 years ago
8 0
You that Mg is the metal if in the periodic table it lands between group 1-12. So yeas Mg is a metal because it lands in group 2.

andrew-mc [135]3 years ago
8 0

Answer: Magnesium loses electrons to form Mg^{2+}

Explanation:

An ionic bond is formed when an element completely transfers its valence electron to another element. Metals donate the electron and forms a positively charged ion called as cation. Non metals accept the electrons and forms a negatively charged ion called as anion.

Electronic configuration of magnesium:

[Mg]:12: 1s^22s^22p^63s^2

Magnesium atom will loose one electron to gain noble gas configuration and form magnesium cation with +2 charge.

[Mg^{2+}]:10:1s^22s^22p^63s^0

Electronic configuration of bromine

[Br]:35:1s^22s^22p^63s^23p^64s^23d^{10}4p^5

Bromine atom will gain one electron to gain noble gas configuration and form bromide ion with -1 charge.

[Br^-]=1s^22s^22p^63s^23p^64s^23d^{10}4p^6

Thus as magnesium forms a cation , it is the metal.

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If you have 85g of sulfur dioxide at STP, how many moles do you have?
Step2247 [10]

Answer: 1.32

Explanation:

Given

85 gm of sulfur dioxide is present at STP

The molar mass of sulfur dioxide is 32+2\times 16=64\ g/mol

The number of moles of sulfur dioxide is

\Rightarrow n=\dfrac{85}{64}\\\\\Rightarrow n=1.32\ \text{mol}

3 0
3 years ago
What processes in the water cycle takes water from oceans and land masses?
krek1111 [17]

Answer:

Water Cycle

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<h2>Importance of the ocean in the water cycle</h2>

  • The ocean plays a key role in this vital cycle of water.
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6 0
2 years ago
7) A block of wood
melamori03 [73]

Answer:

Explanation:

7) A block of wood

has a length of 10.2

cm, a width of 6 cm

and a height of 4.1

cm. The wood has

a total mass of 179

grams. What is the

volume of the

wood and what is

the density of the

wood?

volume = L XW XH=10.2 X 6 X4.1 =250.92cm^3

DENSITY = M/V = 179gm/250.92 cm^3

=0.713 gm/cm^3

5 0
2 years ago
Scintillatium has a halflife of 16 minutes. if a sample has 800 grams, find a formula for its mass after t minutes.
hichkok12 [17]
<span>Halflife is the time needed for a radioactive molecule to decay half of its current mass. If t is the time elapsed, the formula for the halflife would be:
final mass= original mass * </span>\frac{1}{2} ^{\frac{t}{halflife}
<span>
If you put the information of the problem into the formula, the equation will be:
</span>final mass= original mass * \frac{1}{2} ^{\frac{t}{halflife}
final mass= 800g * \frac{1}{2} ^{\frac{t}{16 min}
8 0
3 years ago
4) Balance the following redox reaction in an acidic solution. What are the coefficients in front of H⁺ and Fe3+ in the balanced
Kryger [21]

Answer:

- The coefficients in front of H⁺ and Fe³⁺ are 8 and 5

- There are transferred 5 moles of e-

Explanation:

This is the reaction:

Fe²⁺(aq) + MnO₄⁻(aq) → Fe³⁺(aq) + Mn²⁺(aq)

Let's think the oxidation numbers:

Fe2+ changed to Fe3+

It has increased the oxidation number → OXIDATION

Mn in MnO₄⁻ acts with +7 and it changed to Mn²⁺

It has decreased the oxidation number → REDUCTION

Let's make the half reactions:

Fe²⁺ → Fe³⁺  +  1e⁻    (it has lost 1 mol of e⁻)

MnO₄⁻ + 5e⁻ →  Mn²⁺  (it has gained 5 mol of e⁻)

Now we have to ballance the O. In acidic medium we complete with water as many oxygens we have, in the opposite side. We have 4 O in reactant side, so we fill up with 4 H2O in products side.

MnO₄⁻ + 5e⁻ →  Mn²⁺  + 4H₂O

Now we have to ballance the H, so as we have 8 H in products side, we complete with 8H⁺ in reactants, this is the complete half reaction:

8H⁺  + MnO₄⁻ + 5e⁻ →  Mn²⁺  + 4H₂O

Notice that have 1e⁻ in oxidation and 5e⁻ in reduction. We must multiply (x5) the half reaction of oxidation, so the electrons can be cancelled.

(Fe²⁺ → Fe³⁺  +  1e⁻ ) .5

5Fe²⁺ → 5Fe³⁺  +  5e⁻  

8H⁺  + MnO₄⁻ + 5e⁻ →  Mn²⁺  + 4H₂O

We sum both half reactions:

5Fe²⁺  + 8H⁺  + MnO₄⁻ + 5e⁻ →  5Fe³⁺  +  5e⁻   + Mn²⁺  + 4H₂O

The electrons are cancelled, so the ballanced reaction is this:

5Fe²⁺  + 8H⁺  + MnO₄⁻  →  5Fe³⁺  + Mn²⁺  + 4H₂O

3 0
3 years ago
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