Using the normal distribution relation, the probability that sample will exceed the weight limit is 0.004
<u>Using the relation</u> ::
The mean, μ = np = (162 × 19) = 3078
The standard deviation, σ = 28 × √19 = 122.049
<u>The Zscore</u> :
Zscore = (3401 - 3078) ÷ (122.049)
Zscore = 2.65
Hence,
P(Z > 2.65) = 1 - P(Z < 2.65)
Using a normal distribution table :
P(Z > 2.65) = 1 - 0.9959
P(Z > 2.65) = 0.004
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The is answer E, you have to search for -3 in the x line than search for -2 in the y line
Approximatley 4.39. If thought of like .33X=1.45, then you just divide 1.45 by .33
It really depends on what month or year. but typically a month is 4-5 weeks so it's either 16 or 20 miles
