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postnew [5]
3 years ago
6

there are 57 m&ms in a standard size bag. at 240 calories per bag how many calories is it per m&m

Mathematics
2 answers:
frutty [35]3 years ago
6 0
Divide 240 by 57 and you should get your answer
DENIUS [597]3 years ago
4 0
240/57
240 calories/57 m&ms
about 4.21 calories per m&m
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Answer:


Step-by-step explanation:

a) x>0 → items can not be negative

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5,000-5,000+1.3x<10,000-5,000

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x<3846 items


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3 years ago
|BRAINLIEST|
Mekhanik [1.2K]

Answer:

<em>t</em><em>h</em><em>e</em><em> </em><em>c</em><em>o</em><em>r</em><em>r</em><em>e</em><em>c</em><em>t</em><em> </em><em>a</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em> </em><em>i</em><em>s</em><em> </em><em>C</em><em> </em><em>1</em><em>/</em><em>3</em><em>2</em><em> </em><em>I</em><em>b</em>

Step-by-step explanation:

hope it helps

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3 years ago
0.941176471 to the nearest hundredth ?
Wewaii [24]
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8 0
3 years ago
A package of 5 crackers contains 205 Calories. How many Calories are in one cracker using a double number line
natulia [17]

Answer:

Step-by-step explanation:

since there are 205 calories in 5 crackers we can represent this as

205/5

we need to find how many calories are in one cracker, so lets take "x" as the # of calories in 1 cracker

so

\frac{x}{1} =\frac{205}{5}

cross multiply

5x=205

divide by 5 on both sides

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Number line:

7 0
3 years ago
What is the distance from point (– 1, 3) to the line 3x – 4y = 10?​
natta225 [31]

Answer:

5 units

Step-by-step explanation:

The distance from a point (m, n ) to the line Ax + By + C = 0 is given by

d = \frac{|Am+Bn+C|}{\sqrt{A^2+B^2} }

For the point (- 1, 3 ) , with m = - 1 and n = 3

3x - 4y = 10 ( subtract 10 from both sides )

3x - 4y - 10 = 0

with A = 3 , B = - 4 , C = - 10

d = \frac{|3(-1)+(-4)3-10|}{\sqrt{3^2+(-4)^2} }

   = \frac{|-3-12-10|}{9+16}

   = \frac{|-25|}{\sqrt{25} }

    = \frac{25}{5}

     = 5

5 0
2 years ago
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