Answer:
The product of the slopes of lines is -1.
i.e. m₁ × m₂ = -1
Thus, the lines are perpendicular.
Step-by-step explanation:
The slope-intercept form of the line equation

where
Given the lines
y = 2/3 x -3 --- Line 1
y = -3/2x +2 --- Line 2
<u>The slope of line 1</u>
y = 2/3 x -3 --- Line 1
By comparing with the slope-intercept form of the line equation
The slope of line 1 is: m₁ = 2/3
<u>The slope of line 2</u>
y = -3/2x +2 --- Line 2
By comparing with the slope-intercept y = mx+b form of the line equation
The slope of line 2 is: m₂ = -3/2
We know that when two lines are perpendicular, the product of their slopes is -1.
Let us check the product of two slopes m₁ and m₂
m₁ × m₂ = (2/3)(-3/2
)
m₁ × m₂ = -1
Thus, the product of the slopes of lines is -1.
i.e. m₁ × m₂ = -1
Thus, the lines are perpendicular.
I would say 6 bc it’s a die of 6 and u get it 6 times
Answer:
This really depends on the situation, and many variables. Is there a specific moment? Multiple buttons? Would you mind giving more context or is that it?
Alright,
(a) 2x+4(x-1)=2
2x+4x-4=2---- Distrubution of 4(x-1)
6x-4=2---- Combining like terms
6x=6---- Making -4 equal 0 by adding +4 to both sides
x=1---- Divide the coefficiant (6)
(b) 25-x=15-(3x+10)
25-x=15-3x-10----Distribute the -1
25-x=5-3x---- Combine like terms
25=5-2x---- Make -x equal 0 by adding +x to both sides
20=-2x---- Make 5 equal zero by subtracting 5 (or adding -5) to both sides
-10=x---- Divide by the coefficiant (-2)
(c) 4x= 2x+2x+5(x-x)
4x=2x+2x+5(0)---- Distribute. Alright this might look hard but realy it is 1x-1x so the answer is 0
4x=2x+2x---- 5 times 0 is 0
4x=4x---- Combine like terms
x=x ---- divide by the coefficiant
Alright! Hope this helps! ;)
Answer:
Third option: 2x^3-11x^2+16x-3
Step-by-step explanation:
The product to be found is:

Distributive property will be used for the product:

Multiplication will give us:

The product is: 2x^3-11x^2+16x-3
Hence, third option is the correct answer ..