Step-by-step explanation:
solution,
given
DF = 42
DE = 7x+1
EF = 4x-3
DE = ?
here,
or, DF = DE +EF
or, 42 = 7x+1+4x-3
or, 42 = 11x-2
or, 42+2 = 11x
or, 44/11 = x
or, 4 = x
then,
replacing value of x in DE
DE = 7x+1
= 7*4+1
= 28+1
= 29
You simplify it by doing distributive property like this
(4+2i)(3-i) =12-4i+6i-2i2
now add common like numbers
12+2i-2i2
Now on the i that is squared change the i to a -1 and get this
12+2i+2
Now again add common like numbers and get
14+2i that would be your answer
hope this helped
Answer:
CCCCCCCCCCCCCCCCCCCCCCCCCCCC
Step-by-step explanation:
Answer:
a decimal that terminates
Step-by-step explanation:
it is a decimal that terminates because it stops unlike one that does not terminate
Notice that
y² - 20y + 100 = y² - 2•10y + 10² = (y - 10)²
Then
√(y² - 20y + 100) = y - 10
is equivalent to
√((y - 10)²) = y - 10
|y - 10| = y - 10
If y ≥ 10, then |y - 10| = y - 10, and
y - 10 = y - 10 ⇒ 0 = 0
so there are infinitely many solutions, y ≥ 10.
Otherwise, if y < 10, then |y - 10| = -(y - 10), and
-(y - 10) = y - 10 ⇒ 10 = -10
which is false, so there are no solutions in this case.
