The answer is 78. This is because you change 8 2/3 into a improper fraction which is 26/3. Then do 26/3×9/1. You should cross cancel so cancel out 3 and change it into 1 and change 9 into 3. So now your problem is 26×3=78.
~JZ
Hope it helps.
Answer:
wELL YOU WANT TO GRAB SOME M AND MS AND EAT THEM
Step-by-step explanation:
Answer:
x = 4
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
2(8−12x)+8x=−25x+52
(2)(8)+(2)(−12x)+8x=−25x+52(Distribute)
16+−24x+8x=−25x+52
(−24x+8x)+(16)=−25x+52(Combine Like Terms)
−16x+16=−25x+52
−16x+16=−25x+52
Step 2: Add 25x to both sides.
−16x+16+25x=−25x+52+25x
9x+16=52
Step 3: Subtract 16 from both sides.
9x+16−16=52−16
9x=36
Step 4: Divide both sides by 9.
9x/9 = 36/9
x = 4
Answer:
Step-by-step explanation:
Given:
u = 1, 0, -4
In unit vector notation,
u = i + 0j - 4k
Now, to get all unit vectors that are orthogonal to vector u, remember that two vectors are orthogonal if their dot product is zero.
If v = v₁ i + v₂ j + v₃ k is one of those vectors that are orthogonal to u, then
u. v = 0 [<em>substitute for the values of u and v</em>]
=> (i + 0j - 4k) . (v₁ i + v₂ j + v₃ k) = 0 [<em>simplify</em>]
=> v₁ + 0 - 4v₃ = 0
=> v₁ = 4v₃
Plug in the value of v₁ = 4v₃ into vector v as follows
v = 4v₃ i + v₂ j + v₃ k -------------(i)
Equation (i) is the generalized form of all vectors that will be orthogonal to vector u
Now,
Get the generalized unit vector by dividing the equation (i) by the magnitude of the generalized vector form. i.e

Where;
|v| = 
|v| = 
= 
This is the general form of all unit vectors that are orthogonal to vector u
where v₂ and v₃ are non-zero arbitrary real numbers.
True, because they make up the two line segments make up the right angle