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nikklg [1K]
1 year ago
6

Ask an expert 2+3/10X>=13/20 Solve for inequality Thanks!

Mathematics
1 answer:
dolphi86 [110]1 year ago
8 0

Answer:

The answer is in the picture.

Step-by-step explanation:

2+\frac{3}{10x}\geq\frac{13}{20}  \\\\\frac{3}{10x}\geq\frac{13}{20} -2 \\\\\frac{3}{10x}\geq\frac{13}{20} -\frac{40}{20}  \\\\\frac{3}{10x}\geq-\frac{27}{20}  \\\\3\geq-\frac{27}{20}*10 x \\\\3\geq-\frac{270}{20} x\\\\3\geq-\frac{27}{2} x \\\\3*-\frac{2}{27} \leq x\\\\-\frac{6}{27} \leq x\\\\-\frac{2}{9} \leq x

Also x cannot equal to 0 if you plug in into the original equation the answer is indefinite/not solution.

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2 years ago
The rates of on-time flights for commercial jets are continuously tracked by the U.S. Department of Transportation. Recently, So
tatyana61 [14]

Answer:

The probability that at least 13 flights arrive late is 2.5196 \times 10^{-6}.

Step-by-step explanation:

We are given that Southwest Air had the best rate with 80 % of its flights arriving on time.

A test is conducted by randomly selecting 18 Southwest flights and observing whether they arrive on time.

The above situation can be represented through binomial distribution;

P(X = x) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.........

where, n = number of trials (samples) taken = 18 Southwest flights

           r = number of success = at least 13 flights arrive late

          p = probability of success which in our question is probability that

                flights arrive late, i.e. p = 1 - 0.80 = 20%

Let X = <u><em>Number of flights that arrive late</em></u>.

So, X ~ Binom(n = 18, p = 0.20)

Now, the probability that at least 13 flights arrive late is given by = P(X \geq 13)

P(X \geq 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18)

= \binom{18}{13}\times 0.20^{13} \times (1-0.20)^{18-13}+ \binom{18}{14}\times 0.20^{14} \times (1-0.20)^{18-14}+ \binom{18}{15}\times 0.20^{15} \times (1-0.20)^{18-15}+ \binom{18}{16}\times 0.20^{16} \times (1-0.20)^{18-16}+ \binom{18}{17}\times 0.20^{17} \times (1-0.20)^{18-17}+ \binom{18}{18}\times 0.20^{18} \times (1-0.20)^{18-18}

= \binom{18}{13}\times 0.20^{13} \times 0.80^{5}+ \binom{18}{14}\times 0.20^{14} \times 0.80^{4}+ \binom{18}{15}\times 0.20^{15} \times 0.80^{3}+ \binom{18}{16}\times 0.20^{16} \times 0.80^{2}+ \binom{18}{17}\times 0.20^{17} \times 0.80^{1}+ \binom{18}{18}\times 0.20^{18} \times 0.80^{0}

= 2.5196 \times 10^{-6}.

7 0
3 years ago
Round 9947 to the nearest hundred​
vazorg [7]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
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Can I get a little help here?
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Answer:

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8 0
2 years ago
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