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expeople1 [14]
2 years ago
7

the manager of a six screen movie theater was analyzing the tick sales data for monday through friday of the last week. there we

re 500 tickets sold on wednesday. she noticed that there were more tickets sold on wednesday than on monday and tuesday combined. on Thursday and again on friday more than twice as many tickets were sold as were sold on wednesday. which bar graph could represent the ticket sales

Mathematics
1 answer:
tester [92]2 years ago
4 0

Answer:

Graph A

Step-by-step explanation:

Going through and eliminating graphs based on the criteria, graph A is the only one that shows Wednesday having more tickets sold than Monday and Tuesday combined , as well as having both Thursday and Friday with more than two times the number of tickets sold Wednesday.

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The figure shows a parallelogram inside a rectangle outline: A parallelogram is shown within a rectangle. The length of the rect
Dominik [7]

Answer=5/16 or 0.3125 feet

Step-by-step explanation:

7 0
3 years ago
The list price of a diamond ring is $662. The jeweler is offering a chain discount of 15% less 10%. What is the final net price
Tom [10]
Your answer is 506.44.

multiply 662 x .10 now minus that answer from 662 to get 595.80

now multiply that by .15

now minus that by 595.80

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4 0
3 years ago
Solve y=15(9860)+6997 step by step please!! I'm Stupid :(
puteri [66]
I would probably distribute 15 with the parentheses 15x 9860 which is 147,900 then you would add 6997+147,900
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3 0
3 years ago
Read 2 more answers
Help omg I’m struggling ‍
Harrizon [31]
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7 0
2 years ago
Find the greatest number that divides451, 328 and 673 leaving 1, 4 and 1,respectively as remainders.
Vesna [10]

You're looking for the largest number <em>x</em> such that

<em>x</em> ≡ 1 (mod 451)

<em>x</em> ≡ 4 (mod 328)

<em>x</em> ≡ 1 (mod 673)

Recall that

<em>x</em> ≡ <em>a</em> (mod <em>m</em>)

<em>x</em> ≡ <em>b</em> (mod <em>n</em>)

is solvable only when <em>a</em> ≡ <em>b</em> (mod gcd(<em>m</em>, <em>n</em>)). But this is not the case here; with <em>m</em> = 451 and <em>n</em> = 328, we have gcd(<em>m</em>, <em>n</em>) = 41, and clearly

1 ≡ 4 (mod 41)

is not true.

So there is no such number.

4 0
3 years ago
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