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vazorg [7]
3 years ago
14

F(x)=x2−3x+9f(x)=x2−3x+9

Mathematics
1 answer:
shepuryov [24]3 years ago
5 0
You have copied double of each function, so
(f-g)(x) = x^2-3x+9-3x^3-x^2+4x+9
 
<span>= a. −3x3−x2+x+18</span>
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In two or three sentences explain how you would solve for the real solutions of the following equation: please help asap!!
g100num [7]

the real solutions for the equation x^{3}=-64 are -

x=4,2+-2\sqrt{3i}

Step-by-step explanation:

   x^{3} = - 64

   x^{3} +64  = 0

   We can write 64 as  4^{3}

  x^{3} + 4^{3} = 0

  using the identity  ( x^{3}+y^{3} = (x+y)(x^{2} -xy+y^{2} ) )

we get,

  = (x+4) (x^{2} -x*4+4^{2} )

  = (x+4)(x^{2} -4x+16)    ....................(1)

 solving the quadratic equation  ,

   x^{2} -4x+16 =0

solutions of this quadratic equation can be obtained by

   x=-b +- \sqrt{b^{2}-4ac } /2a

let use y for factors

x=-(-4x)+-\sqrt{(-4x^{2} )-4*x^{2} *16}  / 2*x^{2}

x=4x+-\sqrt{16x^{2} -64x^{2} } /2x^{2}

x=4+-\sqrt{16-64}/2

x=4+-4\sqrt{3i} /2

<u />x=2+-2\sqrt{3i}    ..................(2)

from the equation 1 we have,

x-4=0

which gives solution x=4

and from equation 2 we got  x=2+-2\sqrt{3i}

so the real solutions for the equation x^{3}=-64 are -

x=4,2+-2\sqrt{3i}

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3 years ago
What is the percent increase from 50 to 92
STALIN [3.7K]
Hey!

To find the percentage increase, you must use this formula:

{(50 - 92 / 50] × 100 = 84%

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