Answer:
4(x-7)^2-(x-7)+3 (Assuming t is f)
Step-by-step explanation:
Let s(x)=x-7 and t(x)=4x^2-x+3 .
(t o s)(x)=t(s(x))=t(x-7)
Before I continue this means replace the orginal x in t with x-7.
This will then give you
4(x-7)^2-(x-7)+3
Solve Using the Quadratic Formula (m+ 4)(4m-2)=5(m+3)-10 ..... Use the quadratic formula to find the solutions.
Answer:
Lowest is 100
Highest is 125
Step-by-step explanation:
We use the 5 number summary to be the foundation of a graphical representation referred to as the box plot. One box would move from one quartile which is the lowest quartile Q1 to the another quartile Q3 which is the upper quartile.
Now if a box plot is to be made given the the information in this question, the box is going to go from Quartile 1 to Quartile 3.
Then the Lowest value would be 100 and the highest 125
We have to start by creating an equation.
Cost of System = x
Cost of games = 3x
Thus x + 3x = $500
Now we find x.
4x = 500,
x = 500/4 = 125
So the system is 125,
The games, 125*3 = 375
