Question

Iv)

Answer 1

Answer:

Step-by-step explanation:

Given numbers : 2 , 6, 18, 54

Since common ration between numbers,

$common \ ratio \ in \ GP , \ r = \frac{a_n}{a_{n-1}} = \frac{6}{2} = 3$

So the numbers are in GP.

Now Sum of the numbers = 2 + 6 + 18 + 54 = 80

AM, arithmetic mean between first and last number :

                                                                             $\frac{54+2}{2} = \frac{56}{2} =28$

All the conditions are true.