Is this circuit parallel??????

Physics

1 answer:

kobusy [5.1K]2 years ago

7 0

Answer:

yes it is parrell

Explanation:

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I have to say, i love this kind of problems.

So, we got the linear acceleration, as we all know, linear the acceleration its, in dimensional units:

$[a]=[\frac{distance}{time^2}]$ .

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$[r] = [distance]$

the angular frequency

$[\omega] = \frac{1}{s}$

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Now, the acceleration doesn't have units of mass, so it can't depend on the mass of the particle.

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$a \propto r$ .

The time in the acceleration has exponent -2 As the angular frequency its the only parameter that has units of time, this means that the angular frequency must appear, but, the angular frequency has an exponent of -1, this means it must be squared

$a \propto r \omega^2$ .

We are almost there. If this were any other problem, we would write:

$a = A r \omega^2$

where A its an dimensionless constant. Its common for this constants to appears if we need an conversion factor. If we wanted the acceleration in cm/s^2, for example. Luckily for us, the problem states that there is no dimensionless constant involved, so:

$a = r \omega^2$