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Elena-2011 [213]
4 years ago
7

IF EARTH HAD NO ATMOSPHERE, WOULD A FALLING OBJECT EVER REACH TERMIONAL VELOCITY?

Physics
1 answer:
EleoNora [17]4 years ago
3 0
No.  What most people call 'terminal velocity' is the speed of the falling
object when the downward force of gravity is equal to the upward force
of air resistance.  At that speed, the vertical forces on the object are
balanced, so it stops accelerating, and falls at a constant speed.

If there were no atmosphere, there would be no upward force due to
air resistance.  The falling object would continue to accelerate all the
way down until it went 'splat'.

This is exactly the situation for meteoroids or asteroids falling onto the Moon.
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A balsa wood raft is 1.50 m long, 1.00 m wide, and 0.120 m high. the density of balsa is 380 kg/m^3. what is the mass of the raf
topjm [15]

Answer:

the mass of the raft is 68.4 kg

Explanation:

Since Mass is defined as Volume times Density, start by calculating the volume of the raft:

Volume = length x width x high = 1.5 m x 1.0 m x 0.12 m = 0.18 m^3

and now multiply it times the given density in order to find its mass:

Mass = Volume x Density = 0.18 m^3 x 380 kg/m^3 = 68.4 kg.

Notice that the m^3 units cancel out (they are in numerator and in denominator) leaving just the kg (a unit of mass) in the answer.

Therefore, the mass of the raft is 68.4 kg

4 0
4 years ago
A particle moves in a circular path of radius 0.10 m with a constant angular speed of 5 rev/s. The acceleration of the particle
Darya [45]

Answer:

2.5 m/s²

Explanation:

Acceleration: This can be defined as the rate of change of velocity.

The S.I unit of acceleration is m/s²

For circular motion, the expression for acceleration is given as,

a = ω²r ................ Equation 1

Where a = acceleration of the particle, ω = angular speed of the particle, r = radius of the circular path.

Given: ω = 5 rev/s = 31.42 rad/s, r = 0.10 m.

Substitute into equation 1

a = 5²(0.10)

a = 25(0.10)

a = 2.5 m/s²

Hence the acceleration of the particle = 2.5 m/s²

Hence, none of the option  is correct

7 0
4 years ago
Please answer. Thanks
Brilliant_brown [7]
I believe #1. is the answer " Mitosis and specialization", because all the information needed for growth, development, and reproduction is present in a Zygote
8 0
3 years ago
Which describe the image formed by an object on the center of curvature? Check all that apply.
9966 [12]

The image formed by a concave  mirror with the object placed at the center of curvature is real inverted and formed at the center of curvature. Using the ray diagram a ray from the top of the object to the mirror through f then reflected parallel to the principal axis,then the ray through the center of curvature reflected through the same point both intersect at a plane through center curvature and perpendicular  to the principal axis. The point of intersection forms the top of the image and the center of curvature forms the bottom. Therefore, the correct choices are : real and inverted

5 0
4 years ago
Read 2 more answers
How does density affect the behavior of an object in a liquid or a gas?
BlackZzzverrR [31]
According to Archimedes' Principle, an Object's density determines the depth it will get by displacing the liquid or gas molecules... More the density, more it's depth.
5 0
4 years ago
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