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djyliett [7]
2 years ago
12

3x - 2y < -5

Mathematics
1 answer:
Marysya12 [62]2 years ago
6 0

Answer: A. The wrong region is shaded

Step-by-step explanation:

Let's solve for y in the first equation.

3x−2y<−5

Step 1: Add -3x to both sides.

3x−2y+−3x<−5+−3x

−2y<−3x−5

Step 2: Divide both sides by -2.

\frac{-2y}{-2}< \frac{-3x-5}{-2}

y > \frac{3}{2}x+\frac{5}{2}

graph the equation using the slope \frac{3}{2} and the y-intercept \frac{5}{2}

The line is dotted because it is > (not ≥)

shade in the left side by plugging in (0,0) into x and y and finding

0 is not > than \frac{5}{2}. This means you shade in the side not include the origin.

Do this same thing for the next equation.

Let's solve for y in the second equation.

x+4y>8

Step 1: Add -x to both sides.

x+4y+−x>8+−x

4y>−x+8

Step 2: Divide both sides by 4.

\frac{4y}{4} > \frac{-x+8}{4}

y > \frac{-1}{4}x+2

graph the equation using the slope -\frac{1}{4} and the y-intercept 2

(Dotted line), (plug in 0,0 and find 0 is not > than 2. So shade the region not including the origin (0,0).

Hope this helps.

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Strike441 [17]

Answer:

(q,0)

Step-by-step explanation:

See the diagram given.

It is clear from the coordinates of the points given that point C (0,r) lies on the Y-axis and point E (-q,o) lies on the X-axis. Hence, point D must be on the X-axis.

ΔCDE being an isosceles triangle, the origin of the coordinate axes will be on the DE line and it will be at the midpoint of DE.

Therefore, ΔCDE will be symmetric with respect to the Y-axis and the coordinates of point D will be (q,0). (Answer)

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3 years ago
1.The table provides various values, including all minimums and maximums, of a cosine function f (x) on the interval [0, 2π].
ElenaW [278]

Problem 1

<h3>Answer: D) 2pi</h3>

-------------------

Explanation:

The given table we have is

\begin{array}{|c|c|c|c|c|c|c|} \cline{1-7}\text{Angle} & 0 & \pi/6 & \pi/2 & 5\pi/6 & 3\pi/2 & 2\pi\\ \cline{1-7}f(x) & 1 & 0 & -1 & 0 & 3 & 1\\ \cline{1-7}\end{array}

If you were to graph all those points and draw a cosine curve through them, then the function you should get is

y = 2\cos\left(x+\frac{\pi}{2}\right)+1

The B coefficient is 1, so that leads to a period of

T = 2pi/B

T = 2pi/1

T = 2pi

=============================================

Problem 2

<h3>Answer: C) 343.134 yards</h3>

-------------------

Explanation:

Draw out a triangle with these properties

  • side a = 270
  • side b = 170
  • angle C = 100

We'll use the law of cosines to find side c

c^2 = a^2 + b^2 - 2*a*b*cos(C)

c^2 = 270^2 + 170^2 - 2*270*170*cos(100)

c^2 = 117740.902710

c = sqrt(117740.902710)

c = 343.133943

c = 343.134

=============================================

Problem 3

<h3>Answer: A) 2</h3>

-------------------

Explanation:

If you started with y = sin(x) and applied the transformations stated, then you should end up with y = 2\sin\left(2(x+\frac{\pi}{4})\right)\\\\

From here, plug in x = 0 to find the y intercept.

y = 2\sin\left(2(x+\frac{\pi}{4})\right)\\\\y = 2\sin\left(2(0+\frac{\pi}{4})\right)\\\\y = 2\sin\left(\frac{\pi}{2}\right)\\\\y = 2*1\\\\y = 2\\\\

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3 years ago
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The coefficient of this expression is 5, a coefficient is just the number before a variable.
8 0
4 years ago
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Answer:

439.8 ft²

Step-by-step explanation:

5 0
3 years ago
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