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3 years ago

In Triangle LMN, angle N is a right angle, LM=76 and MN= 40. What is the measure of angle M?

1 answer:

5 0

The quastion is asking us to determine the measure of angle M in a right triangle LMN. We know that angle N is a right angle and that LM = 76 ( Hypotenuse ) and MN = 40 ( Adjacent ). We will use trigonometry: cos M = Adjacent / Hypotenuse = 40 / 76 = 0.5263158; M = cos^(-1) 0.563158; M = 58.242° = 58° 15`. Answer: The measure of angle M is<span> 58°15`.</span>

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The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s

Norma-Jean [14]

The positions when the particle reverses direction are:

$s(t_1)=55ft\\\\s(t_2)=28ft$

The acceleraton of the paticle when reverses direction is:

$a(t_1)=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=18\frac{ft}{s^{2}}$

Why?

To solve the problem, we need to remember that if we derivate the position function, we will get the velocity function, and if we derivate the velocity function, we will get the acceleration function. So, we will need to derivate two times.

Also, when the particle reverses its direction, the velocity is equal to 0.

We are given the following function:

$s(t)=2t^{3}-21t^{2}+60t+3$

So,

- Derivating to get the velocity function, we have:

$v(t)=\frac{ds}{dt}=(2t^{3}-21t^{2}+60t+3)\\\\v(t)=3*2t^{2}-2*21t+60*1+0\\\\v(t)=6t^{2}-42t+60$

Now, making the function equal to 0, to find the times when the particle reversed its direction, we have:

$v(t)=6t^{2}-42t+60\\\\0=6t^{2}-42t+60\\\\0=t^{2}-7t+10\\(t-5)*(t-2)=0\\\\t_{1}=5s\\t_{2}=2s$

We know that the particle reversed its direction two times.

- Derivating the velocity function to find the acceleration function, we have:

$a(t)=\frac{dv}{dt}=6t^{2}-42t+60\\\\a(t)=12t-42$

Now, substituting the times to calculate the accelerations, we have:

$a(t_1)=a(2s)=12*2-42=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=12*5-42=18\frac{ft}{s^{2}}$

Now, substitutitng the times to calculate the positions, we have:

$s(t_1)=2*(2)^{3}-21*(2)^{2}+60*2+3=16-84+120+3=55ft\\\\s(t_2)=2*(5)^{3}-21*(5)^{2}+60*5+3=250-525+300+3=28ft$

Have a nice day!

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3 years ago

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r-ruslan [8.4K]

Answer:

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Step-by-step explanation:

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3 years ago

Given f(x)=x-10. what is f(-7)

Vlad [161]

$f( - 7) = ( - 7) - 10 \\ = -1 7$
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3 years ago

2d +9= 19<br> The solution is d =

Novosadov [1.4K]

${\huge{\boxed{\mathbb{QUESTION}}}$

2d +9= 19

The solution is d =

${\huge{\boxed{\mathbb{ANSWER\:WITH\:EXPLANATION}}}$

Hello there, first we can place our equation, which you have stated

$2d+9=19$ , this algebra, in algebra we want to find the exact value of the variable, or have the variable on one side of the equation.

First we can subtract $9$ with both sides of the equation giving us the result of $2d=10$ , this can also be represented as $2\cdot d=10$ , now just divide both sides of the equation by $2$ , our answer is $d=5$ .