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2 years ago

(3 x 1) + (6 x 1 - 100

Mathematics

1 answer:

alexira [117]2 years ago

3 0

Answer: 3.06

Step-by-step explanation:

PEMDAS

Parenthesis first:

(3x1)= 3

(6x1/100)= 0.06

Finally add and then you have 3.06.

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What’s the correct answer for this question?

weqwewe [10]

Answer:

Last answer choice

Step-by-step explanation:

The AAS congruence theorem uses two adjacent angles, followed by a side length on the side (not in between the angles.) Therefore, the first answer is ruled out (because it deals with angles and not sides), and the second answer is ruled out because it involves side lengths between angles. LP=MO may be true, but it does not compare the two triangles that we are interested in. However, the last answer choice is correct, because a midpoint divides a line exactly in half, meaning that both halves are the same length and therefore congruent. Therefore, the last answer choice is correct. Hope this helps!

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3 years ago

Factor the expression below using the greatest common factor 6p3- 2p2 - 8p

miss Akunina [59]

Answer:

The Factor of expression using the greatest common factor is $2p(3p^2- p-4)$

Step-by-step explanation:

Consider the provide expression.

$6p^3- 2p^2 - 8p$

We need to Factor the expression using the greatest common factor.

First look at the coefficients of the variable.

The coefficients are the factor of 2.

Variable p is the greatest common factor in the provided expression.

$2p\times 3p^2- 2p\times p- 2p\times 4$

$2p(3p^2- p-4)$

Hence, the Factor of expression using the greatest common factor is $2p(3p^2- p-4)$ .

7 0

3 years ago

What is the lateral surface area? plz help. I will mark brainliest asap!!!!

nevsk [136]

Answer:

301.44

Step-by-step explanation:

4*4*3.14*2=100.48

8*3.14*8=200.96

100.48+200.96=301.44

7 0

3 years ago

There is a bag filled with 5 blue, 6 red and 2 green marbles.

Kipish [7]

Answer:

the probability of getting 2 greens is 2/13

Step-by-step explanation:

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3 years ago

Given the following right triangle, find cose, sine, tane sececsce, and cote. Do not

IgorLugansk [536]

Step-by-step explanation:

Use the Pythagorean theorem:

$leg^2+leg^2=hypotenuse^2$

We have

$leg=4,\ hypotenuse=10$

Substitute:

$4^2+leg^2=10^2$

$16+leg^2=100$ <em>subtract 16 from both sides</em>

$leg^2=84\to leg=\sqrt{84}\\\\leg=\sqrt{(4)(21)}\\\\leg=\sqrt4\cdot\sqrt{21}\\\\leg=2\sqrt{21}$

$sine=\dfrac{opposite}{hypotenuse}\\\\cosine=\dfrac{adjacent}{hypotenuse}\\\\tangent=\dfrac{opposite}{adjacent}\\\\cotangent=\dfrac{adjacent}{opposite}\\\\secant=\dfrac{hypotenuse}{adjacent}\\\\cosecant=\dfrac{hypotenuse}{opposite}$

Substitute:

$hypotenuse=10,\ opposite=4,\ adjacent=2\sqrt{21}$

$\sin\theta=\dfrac{4}{10}=\dfrac{2}{5}\\\\\cos\theta=\dfrac{2\sqrt{21}}{10}=\dfrac{\sqrt{21}}{5}\\\\\tan\theta=\dfrac{4}{2\sqrt{21}}=\dfrac{2}{\sqrt{21}}\cdot\dfrac{\sqrt{21}}{\sqrt{21}}=\dfrac{2\sqrt{21}}{21}\\\\\cot\theta=\dfrac{2\sqrt{21}}{4}=\dfrac{\sqrt{21}}{2}\\\\\sec\theta=\dfrac{10}{2\sqrt{21}}=\dfrac{5}{\sqrt{21}}\cdot\dfrac{\sqrt{21}}{\sqrt{21}}=\dfrac{5\sqrt{21}}{21}\\\\\csc\theta=\dfrac{10}{4}=\dfrac{5}{2}$

5 0

3 years ago

(3 x 1) + (6 x 1 - 100​

(3 x 1) + (6 x 1 - 100