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2 years ago

Need help with balancing equations

Chemistry

1 answer:

solniwko [45]2 years ago

7 0

The balanced equation of the reaction shows that the mole of atoms on both sides of the reaction are equal.

<h3>What are balanced chemical equations?</h3>

Balanced chemical equations are equations in wgich the moles of each species on both sides of the reaction are equal.

To balance chemical equations, numerical coefficients are placed in front of the species in the reaction.

The balanced equations of the reaction are as follows:

$3Pd + 4H_3PO_4 \rightarrow Pd_3(PO_4)_4 + 6H_2 \\$

$C_{11}H_{24} + 17O_2 \rightarrow 11CO_2 + 12H_2O \\$

$2Al(HCO_3)_3 + 3H_2SO_4\rightarrow Al_2(SO_4)_3 +6CO_2 +6H_2O \\$

Therefore, the balanced equation of the reaction shows that the mole of atoms on both sides of the reaction are equal.

Learn more about balancing equations at: brainly.com/question/11904811

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SnO2 + 2H2 >>> Sn + 2H2O

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Hands on mole activity

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Explanation:

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The overall reaction of ozone reacting to form oxygen has been proposed to occur in a reaction mechanism of: What is the role of

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Answer:

3) O(g) is an intermediate; 2O3(g)→3O2(g)

Explanation:

The decomposition of ozone to yield oxygen occurs in a sequence of steps. The various non-elementary reactions involved constitute the reaction mechanism. In the sequence of reaction steps O(g) serves as an intermediate.

The overall reaction involves the conversion of two moles of ozone to three moles of oxygen as shown in the answer. Thus the O(g) is merely a reaction intermediate.

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3 years ago

Water is placed in a graduated cylinder and the volume is recorded as 43.5 ml. a homogeneous sample of metal pellets with a mass

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The volume displaced is exactly the same as that of the body (The Eureka fro Archimedes!)

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3 years ago

Answer the following questions about the solubility of AgCl(s). The value of Ksp for AgCl(s) is 1.8 × 10−10.

Katyanochek1 [597]

Answer:

[Ag⁺] = 1.3 × 10⁻⁵M

s = 3.3 × 10⁻¹⁰ M

Because the common ion effect.

Explanation:

1. Value of [Ag⁺] in a saturated solution of AgCl in distilled water.

The value of [Ag⁺] in a saturated solution of AgCl in distilled water is calculated by the dissolution reaction:

AgCl(s) ⇄ Ag⁺ (aq) + Cl⁻ (aq)

The ICE (initial, change, equilibrium) table is:

AgCl(s) ⇄ Ag⁺ (aq) + Cl⁻ (aq)

I X 0 0

C -s +s +s

E X - s s s

Since s is very small, X - s is practically equal to X and is a constant, due to which the concentration of the solids do not appear in the Ksp equation.

Thus, the Ksp equation is:

Ksp = [Ag⁺] [Cl⁻]

Ksp = s × s

Ksp = s²

By substitution:

1.8 × 10⁻¹⁰ = s²

s = 1.34 × 10⁻⁵M

Rounding to two significant figures:

[Ag⁺] = 1.3 × 10⁻⁵M ← answer

2. Molar solubility of AgCl(s) in seawater

Since, the conentration of Cl⁻ in seawater is 0.54 M you must introduce this as the initial concentration in the ECE table.

The new ICE table will be:

AgCl(s) ⇄ Ag⁺ (aq) + Cl⁻ (aq)

I X 0 0.54

C -s +s +s

E X - s s s + 0.54

The new equation for the Ksp equation will be:

Ksp = [Ag⁺] [Cl⁻]

Ksp = s × ( s + 0.54)

Ksp = s² + 0.54s

By substitution:

1.8 × 10⁻¹⁰ = s² + 0.54s

s² + 0.54s - 1.8 × 10⁻¹⁰ = 0

Now you must solve a quadratic equation.

Use the quadratic formula:

$s=\dfrac{-0.54\pm\sqrt{0.54^2-4(1)(-1.8\times 10^{-10})}}{2(1)}$

The positive and valid solution is s = 3.3×10⁻¹⁰ M ← answer

3. Why is AgCl(s) less soluble in seawater than in distilled water.

AgCl(s) is less soluble in seawater than in distilled water because there are some Cl⁻ ions is seawater which shift the equilibrium to the left.

This is known as the common ion effect.

By LeChatelier's principle, you know that an increase in the concentrations of one of the substances that participate in the equilibrium displaces the reaction to the direction that minimizes this efect.

In the case of solubility reactions, this is known as the common ion effect: when the solution contains one of the ions that is formed by the solid reactant, the reaction will proceed in less proportion, i.e. less reactant can be dissolved.

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