Answer: The new penny is not pure copper
Explanation:
Density 
is defined as a relation between the mass 
and the volume 
:
Now, we are told the density of pure copper is:
And we are given the mass and volume of the new penny, with which we can calculate its density:
As we can see the density of this penny is not equal to the density of pure copper, hence the new penny is not pure copper.
Chemical equation:
<span>CH</span>₃<span>COOH + H</span>₂<span>O = CH</span>₃<span>COO</span>⁻<span> + H</span>₃<span>O</span>⁺
hope this helps!
That is a graph read both sides and you see speed and distance which must mean that someone is graphing peoples speed.
The initial sample has a molecular formula of MnSO₄·H₂O. This molecule is a hydrate as it has a unit of water within its structure for every molecule of MnSO₄. This sample is being dehydrated to remove the water to give.
MnSO₄·H₂O → MnSO₄ + H₂O
MnSO₄·H₂O has a molecular mass of 169.02 g/mol. While MnSO₄ has a molecular mass of 151 g/mol. Water has a molecular mass of 18.02 g/mol. We now can use the ratio of the mass of water to the mass of the initial sample to determine the percentage of each component by mass.
% water by mass:
18.02/169.02 x 100% = 10.7% Water by mass.
% MnO₄ by mass:
151/169.02 x 100% = 89.3% MnSO₄ by mass.
Water makes up 10.7% of the initial mass of MnSO₄·H₂O.
(x1,y1) (x2,y2)
(32,15) (212,135)
y = mx + b
m=(y2-y1)/(x2-x1)
m=.66667
y = .66667*(x) + b
Plug in #s to test for b value
15 = .66667*(32) + b
b = -6.334
y = mx + b
y = .6667*(x) + (-6.334)
F = .6667*(F) + (-6.334)
F = (.6667*(F) = -6.334
(F - .6667F) = -6.334
F(1 - .6667) = -6.334
F = -19
ThermX = F @ -19 degrees
Brainliest please!
