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zavuch27 [327]
3 years ago
11

Electrons are ejected from a surface with speeds ranging up to 1380 km/s when light with a wavelength of 173 nm is used. What is

the work function of this surface? The speed of light is 2.99792 × 108 m/s and Planck’s constant is 6.62607 × 10−34 J · s. Answer in units of eV.
Chemistry
1 answer:
mixer [17]3 years ago
8 0

Answer:

ΔE(work)= 692 Kj/mole e⁻ = 4.32 x 10²⁴ eV/mole e⁻

Explanation:

ΔE = hc/λ = (6.63 x 10⁻³⁴j·s)(2.99792 x 10⁸m/s)/(1.73 x 10⁻⁷m) = 1.15 x 10⁻¹⁸j/e⁻ x 6.023 x 10²³ e⁻/mole = 691,999 j/mole e⁻ = 692 Kj/mole e⁻ x 6.24 x 10²¹ eV/KJ = 4.32 x 10²⁴ eV/mole e⁻

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Name the following compound: HNO3 Hydrogen nitrate Hydrogen nitrite Nitric acid Nitrous acid
wariber [46]

The compound HNO3 is called nitric acid.

HNO3 is a covalent compound and  a strong acid which ionizes in water into H+ (proton) and NO3- (nitrate ion).

HNO3 (aq) ↔ H+(aq) + NO3-(aq)

Ans: HNO3 = Nitric Acid

[On a side note: Nitrous acid is HNO2]

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3 years ago
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What kind of graph would best show the info in the data table below?
Rasek [7]

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3 years ago
A sample of argon gas (molar mass 40 g) is at four times the absolute temperature of a sample of hydrogen gas (molar mass 2 g).
katen-ka-za [31]

Answer:

Ratio of Vrms of argon to Vrms of hydrogen = 0.316 : 1

Explanation:

The root-mean-square speed measures the average speed of particles in a gas, and is given by the following formula:  

Vrms = \sqrt{3RT/M}

where R is molar gas constant = 8.3145 J/K.mol, T is temperature in kelvin, M is molar mass of gas in Kg/mol

For argon, M = 40/1000 Kg/mol = 0.04 Kg/mol, T = 4T , R = R

Vrms = √(3 * R *4T)/0.04 = √300RT

For hydrogen; M = 1/1000 Kg/mol = 0.001 Kg/mol, T = T, R = R

Vrms = √(3 * R *T)/0.001 = √3000RT

Ratio of Vrms of argon to that of hydrogen = √300RT / √3000RT = 0.316

Ratio of Vrms of argon to that of hydrogen = 0.316 : 1

4 0
4 years ago
A closed, adjustable cylinder containing 6.2 moles of oxygen gas has a volume of 4.3 liters and a pressure of 3.8 atmospheres. I
il63 [147K]

Answer:

The new pressure is 1.05 atm

Explanation:

Step 1: Data given

Number of moles oxygen gas = 6.2 moles

Volume of the cylinder = 4.3 L

Pressure of the gas = 3.8 atm

The volume changed to 15.5 L

Step 2: Calculate the new pressure

P1*V1 = P2*V2

⇒with P1 = the initial pressure of the gas = 3.8 atm

⇒with V1 = the initial volume = 4.3 L

⇒with V2 = the increased volume = 15.5 L

⇒with P2 = the new pressure = TO BE DETERMINED

3.8 atm * 4.3 L = 15.5 L * P2

P2 = (3.8 atm *4.3 L) / 15.5 L

P2 = 1.05 atm

The new pressure is 1.05 atm

5 0
3 years ago
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