Answer:
The correct answer is: pH= 4.70
Explanation:
We use the <em>Henderson-Hasselbach equation</em> in order to calculate the pH of a buffer solution:
Given:
pKa= 4.90
[conjugate base]= 4.75 mol
[acid]= 7.50 mol
We calculate pH as follows:
pH = 4.90 + log (4.75 mol/7.50 mol) = 4.90 + (-0.20) = 4.70
Answer:
The pH of solution is 2.88 .
Explanation:
The reaction is :
We know, for this reaction is =
Also, since volume of water is 1 L.
Therefore, molarity of solution is equal to number of moles.
Also,
Let, amount of produce is x.
So,
We know,
Therefore, pH of solution is 2.88 .
Hence, this is the required solution.