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mote1985 [20]
2 years ago
14

Which of the following is the best hypothesis?

Chemistry
2 answers:
tia_tia [17]2 years ago
8 0
B is correct

Which of the following is the best hypothesis?
OA. Physical changes are much less interesting to watch than
chemical changes.
B. If sodium carbonate is added to vinegar, the reaction will absorb
heat.
C. Tearing a piece of paper is an example of a physical change.
D. Some chemical reactions absorb heat, and others release heat.
SUBMIT
Help me y’all
DerKrebs [107]2 years ago
4 0

Answer:

B.) If sodium carbonate is added to vinegar, the reaction will absorb heat.

Explanation:

A.) is incorrect because this is not testable. Rather, it is just an opinion that cannot be proven correct or incorrect.

B.) is correct because this statement is testable. Tests need to be run to determine the accuracy of the statement.

C.) is incorrect because this statement explains something that does not need to be tested. It is an example of a physical change when one tears a piece of paper.

D.) is incorrect because this is already a true statement. It is obvious that not all reactions absorb/release heat. While tests could be run to further prove this statement true, it is already considered accurate.

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Step 1 : Write balanced chemical equation

The balanced chemical equation for the reaction between iodine gas and chlorine gas is given below.

I_{2}  (g) + Cl_{2}  (g) ----->  2 ICl (g)

Step 2 : Set up ICE table

We will set up an ICE table for the above reaction

Following points are considered while drawing ICE table

- The initial concentration of product is assumed as 0

- The change in concentration (C) is assumed as x. Change (x) is negative for reactants and positive for products

- The coefficients in balanced equation are considered while writing C values

Check attached file for ICE table

Step 3 : Set up equilibrium constant equation

The equation for equilibrium constant can be written as

K_{eq} = \frac{[ICl]^{2}}{[I_{2}][Cl_{2}]}

Step 4 : Solving for x

Keq at 298.15 K is given as 81.9

Let us plug in the equilibrium values (E) for I₂, Cl₂ and ICl from ICE table

81.9 = \frac{(2x)^{2}}{(0.437-x) (0.269-x)}

81.9 = \frac{(2x)^{2}}{x^{2} -0.706x + 0.118}

(2x)^{2} = 81.9 [ x^{2} -0.706x + 0.118]

4x^{2} = 81.9x^{2} -57.8x +9.66

77.9x^{2} -57.8x+9.66 = 0

Solving the above equation using quadratic formula we get

x = 0.488 or x = 0.254

The value 0.488 cannot be used because the change (C) cannot be greater that initial concentration of the reactants.

Therefore the change in concentration of the gases during the reaction is 0.254 M

Hence, x = 0.254 M

From the ICE table, we know that the equilibrium concentration of ICl is 2x

[ICl]_{eq} = 2 ( 0.254) = 0.508 M

The concentration of ICl when the reaction reaches equilibrium is 0.508 M

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