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Andre45 [30]
2 years ago
15

How to make 21 mins into a fraction

Mathematics
2 answers:
3241004551 [841]2 years ago
8 0

Answer:

aDSADASDSADSADSAD

Step-by-step explanation:

alexira [117]2 years ago
6 0
Depends what you mean

21 minutes over 60 minutes (in an hour)

21/60=7/20
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Please find the value?
lesantik [10]

Answer:

Step-by-step explanation:

By the marks on the angles of this triangle, it is isosceles.  By the Isosceles Triangle Theorem, if 2 angles of a triangle have the exact same measure, then the sides across from those angles have the exact same measure as well.  That means that, algebraically,

5x - 2 = 33 and

5x = 35 so

x = 7

8 0
3 years ago
Plsanswer these 2 questions
makkiz [27]

Answer:

color in 8 triangels


8 0
3 years ago
Which expression is equivalent to 3√50*√22 ?<br><br> 30√22<br><br> 15√11<br><br> 15√22<br><br> 30√11
shtirl [24]
I hope this helps you

4 0
4 years ago
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What is the complement of a 42 degree angle
coldgirl [10]
Do 90 degrees minus 42 degrees
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3 0
4 years ago
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Consider the following binomial experiment. The probability that a green jelly bean is chosen at random from a large package of
Flura [38]

Answer:

There is a 5.79% probability that at most 2 jelly beans are chosen.

Step-by-step explanation:

For each jelly bean chosen, there are only two possible outcomes. Either it is green, or it is not. This is why we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

There are 13 jelly beans, so n = 13.

The probability that a green jelly bean is chosen at random from a large package of jelly beans is 2/5. This means that p = 0.4.

If Sally chooses 13 jelly beans, what is the probability that at most two will be green jelly beans?

This is

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2).

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{13,0}.(0.4)^{0}.(0.6)^{13} = 0.0013

P(X = 1) = C_{13,1}.(0.4)^{1}.(0.6)^{12} = 0.0113

P(X = 1) = C_{13,2}.(0.4)^{2}.(0.6)^{111} = 0.0453

So

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0013 + 0.0113 + 0.0453 = 0.0579.

There is a 5.79% probability that at most 2 jelly beans are chosen.

8 0
3 years ago
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