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2 years ago

Anyone know inverse operations, cause I am confused, I looked online and it said

Mathematics

2 answers:

bija089 [108]2 years ago

8 0

Answer:

For inverse operations, it helps make solving equations easier. Say if you'd rather add than subtract, then you can do the inverse of a negative equation.

Inverse operations are also very helpful for linear equations.

To find the inverse of an equation, we change the plus sign to a negative sign. Then, we switch the first number and the answer.

Ex:

13 - 2 = 11 (now change plus to minus)

13 + 2 = 11 (not the answer yet)

Now we switch the first number with the answer!

11 + 2 = 13

Hope this helped, I tried to explain it easily.

Vesna [10]2 years ago

6 0

11+2=13 that’s the answer maybe

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3 years ago

Find the area of the shape below. Break<br> the larger shape into smaller pieces if needed.

NikAS [45]

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116 Sq inches

Step-by-step explanation:

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2 years ago

There is 5/6 of an apple pie left from dinner.Tomorrow,Victor plans to eat 1/6 of the pie that was left.How much of the whole pi

kow [346]

Answer:

1=2/3 reduced or 4/6 full

2=8/3

Step-by-step explanation:

4 0

3 years ago

I need help writing the first 5 terms of the sequence!

Angelina_Jolie [31]

The first five terms of the sequence are 1, 4, 7, 10, 13.

Solution:

Given data:

$a_{1}=1$

$a_{n}=a_{n-1}+3$

General term of the arithmetic sequence.

$a_{n}=a_{n-1}+d$ , where d is the common difference.

d = 3

$a_{n}=a_{n-1}+3$

Put n = 2 in $a_{n}=a_{n-1}+3$ , we get

$a_{2}=a_1+3$

$a_{2}=1+3$

$a_2=4$

Put n = 3 in $a_{n}=a_{n-1}+3$ , we get

$a_{3}=a_2+3$

$a_{3}=4+3$

$a_3=7$

Put n = 4 in $a_{n}=a_{n-1}+3$ , we get

$a_{4}=a_3+3$

$a_{4}=7+3$

$a_4=10$

Put n = 5 in $a_{n}=a_{n-1}+3$ , we get

$a_{5}=a_4+3$

$a_{5}=10+3$

$a_5=13$

The first five terms of the sequence are 1, 4, 7, 10, 13.

3 0

3 years ago

Solve the system and enter the smallest x-coordinate first

ankoles [38]

Answer:
(2,-3)(6,5)
Step-by-step explanation:
We can use substitution to get the equation: x^2-6x+5 = 2x-7
Solve:
x^2-6x+5 = 2x-7
x^2 = 8x-12
x^2-8x+12 = 0 (we now have a polynomial)
(x-6)(x-2) = 0 (set each equation to equal 0 and solve)
x-6 = 0 --> x=6
x-2 = 0 --> x=2
To get the Y coordinates:
y=2(2)-7 --> y = -3
y = 2(6)-7 --> y = 5

Check work:
5 = 6^2-6(6)+5 --> 5 = 36-36 +5 --> 5=5
-3 = 2^2-6(2)+5 --> -3 = 4-12+5 --> -3=-3

4 0

1 year ago