<span>let's call the width w
l= w+6 [because l is 6 meters more than width]
Perimeter = width+width+length+length
=w+w+ (w+6) + (w+6 ) [ I substituted w+6 in place of l]
so 4w+ 12=36
4w= 36-12
4w=24
w=24/4
w=6
since length = w+6, this means that length is 6+6= 12
so width= 6 m and length = 12 m</span>
Answer: 0.2772 or 27.72%
<em><u>WORK </u></em><em>↓</em>
0.2772/ 1 × 100/100 = 27.72/100
* Hopefully this helps:) Mark me the brainliest:)!!!!
C expression equivalent to -3*(4/-5)
Answer:
There are 5,827,360 different outcomes.
Step-by-step explanation:
Fundamental counting principle:
States that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are p*q ways to do both things.
In each party:
The order in which the people are selected is important(first is chair, second vice chair), which means that the permutations formula is used to solve this question.
Permutations formula:
The number of possible permutations of x elements from a set of n elements is given by the following formula:

Reds:
Two from a set of 44. So

Blues:
Two from a set of 56. So

How many different outcomes are there for the chair and vice chair elections of both parties?
Considering both, by the fundamental counting principle:
1892*3080 = 5827360
There are 5,827,360 different outcomes.
Answer: the answer is D
Step-by-step explanation:I had that question on a quiz