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The Mean Value Theorem:
If a function is continuous on [ a, b ] and differentiable on ( a , b ) than there is a point c in ( a, b ) such that:
f ` ( c )= ( f ( b ) - f ( a ) ) / ( b - a )
f ` ( c ) = ( f ( 2 ) - f ( 0 ) ) / ( 2 - 0 )
f `( x ) = 10 x - 3
f ` ( c ) = 10 c - 3
2 f ` ( c ) = 16 - 2
f ` ( c ) = 7
7 = 10 c - 3
c = 1
Answer:
Yes, the function is continuous on [ 0, 2 ] and differentiable on ( 0, 2 ).
The dog weighs 12 lbs.
The cat weighs 2/3 as much as the dog
- Divide 12 by 3
= 4
- Then multiply by 2
= 8
His cat weighs 8 pounds.
2n-4= n-10
-n. -n
n-4=-10
+4. +4
n=-6
Final answer: -6
<span>B)
8 ft
6, 8, 10 are lengths of a Pythagorean triple
6^2 + 8^2 = 10^2</span><span>
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