Here it is given that AB || CD
< EIA = <GJB
Now
∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)
∠EIA ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)
∠IKL + ∠IKC 180° and ∠DLH + ∠JLD =180° (Linear Pair Theorem)
So
m∠IKL + m∠IKC = 180° ....(1)
But ∠IKC ≅ ∠JLD
m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)
So we have
m∠IKL + m∠JLD = 180°
∠IKL and ∠JLD are supplementary angles.
But ∠DLH and ∠JLD are supplementary angles.
∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)
No, 3/4 is greater than 5/12.
Answer:
P=6x+8
A=2x^2+11x-21
Step-by-step explanation:
Perimeter:
P=2(x+7)+2(2x-3)
P=6x+8
Area:
A=(x+7)(2x-3)
A=2x^2+11x-21
The answer is <span>SAS (side, angle, side) SAS stands for "side, angle, side" and means that we have two </span>triangles<span> where we </span>know<span> two sides and the included angle are equal. If two sides and the included angle of one </span>triangle<span> are equal to the corresponding sides and angle of another </span>triangle, thetriangles<span> are </span>congruent<span>.</span>
